GED 150 Mathematics Challenge Exam Solutions - Problems & Answers

This document presents a comprehensive set of solutions for a GED 150 Mathematics Challenge Exam, covering a wide range of mathematical concepts. The solutions address problems involving whole numbers, fractions, decimals, percentages, ratios, proportions, and basic statistics. Each solution is detailed, showing the steps and calculations required to arrive at the correct answer. The problems include various question types, such as numerical calculations, word problems, and multiple-choice questions, ensuring a thorough understanding of the material. The document aims to assist students in understanding and mastering the core concepts of basic college mathematics, making it a valuable resource for exam preparation and general study. The solutions are organized logically, making it easy for students to follow the problem-solving process and learn from the examples provided.

Mathematics
1 Solution:- a. Six hundred million, forty thousand
600= Six hundred million
040,000 = forty thousand
2 Solution:- b. 16 R 5
325/20= 16 R 5
3. Solution:- a. 2250 matches per carton
A box contains matches =150
Total boxes of matches=15
No. of matches in cartoon=150*15
=2250 matches
4 Solution:- a. 49,004
55,656 – 6652 =49004
5. Solution:- d. 1 hundreds + 4 tens + 6 ones
Expand notation of no.- 1-one
4-four
6-six
6. Solution:- b. 91,531
85355+6176=91531
7. Solution:- d. 125

5^3=5*5*5
=125
8.Solution:- a. 455
513 - 58 =455
9. Solution:- c. 638,997
Six hundred thirty-eight thousand =638
Nine hundred ninety-seven =997
10.Solution:- c. 43,804
13,475 + 30, 329 =43,804
11. Solution:- a. 2, 3, 6
6486/2 =3243 R 0
6486/3 =2162 R 0
6486/4 =1621 R 2
6486/5=1297 R 1
6486/6 = 1081 R 0
6486/8 = 801 R 6
6486/9 =720 R 6
6486/10 =648 R 6
12.Solution:- c. 1, 3, 5, 9, 15, 45
45=1*3*3*5
45=1*3*15

45= 1*5*9
45=1*45
All factors 45= 1, 3, 5, 9, 15, 45
13. Solution:- c. 3/7
Total blocks = 7
Shaded blocks =3
Object is shaded =3/7
14 Solution:- d. 9/2 lots
Land developer have lands =9 acres
Each lot development= ½
Land developer in 9 acres =9*(1/2)
=9/2 lots
15 Solution:- d. 1/2
2/4=(1*2)/(2*2)
= 1/2
16 Solution:- c. 57/14
(19/5) x (15/14) =(19 x15)/(5 x14)
=(19 x5 x3)/(5 x3 x14)
=57/14
17 Solution:-c. 60 patrons
Capacity of restaurant = 80 patrons
Part of restaurant full =3/4

No. of patrons = 80x3/4
= 60 patrons
18 Solution:- d. 5/4
Reciprocal = Change numerator into denominator 4 become 5
= Change denominator into numerator 5 become 4
Before value = 4/5
After Reciprocal value = 5/4
19. Solution:- b. 4/10
Total no. of shapes =10
Shapes fill = 4
Shaded area = 4/10
20. Solution:- A true, B false
Factor 0f 9 =3x3
Therefore a no. divisible by 9 , it must be divisible by 3.
Case of B 3 is smallest factor than 9 so it can’t divisible by 9.
21. Solution:- c. 2/15 mi
Saji swims every day =1/3 mi
Already swum = 1/5 mi
Further swim = (1/3)-(1/5)
= (5-3)/15
= 2/15 mi

22 Solution:- a. The 56th batch
Tom tests = every 8th batch
Larry tests= every 28th batch
Tom will test batches = 8,16,24,32,40,56,64,72,80
Larry will test batches = 28,56,74,130,158,186
Both will test = 56 batch
23 Solution:- c. 117
Least common factor of 9 ,13 is 9x13 =117
24 Solution:- b. 630 seconds
Three Planets make a revolution
Revolution of innermost planet = 18 seconds
Revolution of Middle planet = 30 seconds
Revolution of outermost planet = 42 seconds
Planets will Align at
By Taking LCM (Least common factor)
LCM of (18, 30,42)
18 = 2x 3 x 3
30 = 2x 3 x 5
42 = 2 x 3 x 7
LCM of (18, 30,42) = 2 x 3 x 3 x 5 x 7
LCM of (18, 30,42) = 630 seconds

25 Solution:- b. 7/10
= (3/4) - (1/20)
=(15-1)/20
=7/10
26 Solution:- a. 19/30 hr
Erika spent discovery and history channel website = 5/6 hr
Erika spent history channel website = 1/5 hr
Erika spent discovery channel website = (5/6)-(1/5)
= (25-6)/30
= 19/30 hr
27 Solution :- c. 12/17
(6/17) + (6/17) = (6+6)/17
= 12/17
28 Solution:- a. 5/12
One partner owns a sailboat on Lake Michigan =7/12
Second partner owns a sailboat on Lake Michigan =1/6
Third partner owns a sailboat on Lake Michigan = (7/12)-(1/6)
= (7-2)/12
= 5/12

29 Solution:- d. 528
Factor of 12 = 1x2x2x3
Factor of 44 = 1x2x2x11
Factor of 16 = 1x2x2x2x2
Factor of 12 =1x2x2x2x11
Least common factor =1x2x2x2x6x11
=528
30 Solution:- b. y = 9/25
Y = (11/15)-(2/25)
= (55-10)/125
= 45/125
= 9/25
31. Solution:- b. 9 pieces
Length of cable = 50.4
Piece required from cable = (50.4)/(5.6)
= 9 pieces
32. Solution:- c. Nine hundred eighty-one and eighty-five tenths
33 Solution:- d. $159,300,000,000
1 billion = 1x 10^9
34. Solution:- c. 0.23 hr
Distance for a drive = 15 miles
Speed = 64 miles per hour
Time = Distance/ Speed

Time= (15 miles)/(64 miles per hour)
=0.23 hr
35. Solution:- a. 0.87
13/15 in decimal = 0.8666
Round to the nearest hundredth = 0.87
36. Solution:- b. 6.500
Round to the nearest thousandth = 6.500
37. Solution:- a. 14.3¢
13 packets of cookies = $27.95
1 Packet = 15 cookies
13 packets = 13x15
= 195
Cost of each cookie = 27.95/195
=14.3¢
38. Solution:- a. 2
9.85/5 = 1.97
The quotient by first rounding = 1.97 + 0.3
= 2
39. Solution:- b. 8.9539
0.6861 + t = 9.64
t = 9.6400 – 0.6861
t = 8.9539

40. Solution:- b. 0.645
No. of women in theater production = 238
No. of Men in theater production = 131
Ratio = No. of women/Total no. of population
Ratio = (238)/(238+131)
= 0.645
41. c. 4 ft
Height of figure 1 (h1) = h ft
Length of figure 1(l1)= 10 ft
Height of figure 2 (h2)= 6 ft
Length of figure 2(l2) = 15 ft
Missing length = (h1:l1)/(h2:l2)
(h/6) = (10/15)
h= (10x6)/15
h= 4 ft
42. Solution:- d. x = 2, y = 3
On comparing figures missing length = 1/2x (given lengths)
Therefore x= (1/2) x 4 =2
Y = (1/2) x 6 =3
43. Solution:- b. 49.83 cents/oz
Yogurt 6-pack of 4-oz containers cost is = $2.99
Unit price per ounce = $2.99/6
= 49.83 cents/oz
44. Solution:- a. $4976.55
1 U.S. dollar was worth = 11.059 Mexican pesos

Worth of 450 U.S. dollars = (450 x 11.059)
= $4976.55
45. Solution:- Brand A: 11.25 oz for $2.59
Price for Brand A = 11.25/2.59
= 0.2302
Price for Brand B = 10.25/2.56
= 4.0
Lower unit price is of Brand A.
46. Solution:- d. 5.2 yd
1.5 inches = 45 yards
1 inch = 45/1.5
1 inch = 30 yards
Length = (12x13)/30
= 5.2 yd
47. Solution:- b. x = 10.5
According to proportionality
(x/6) = (14/8)
8x = 14x6
x = (14x6)/8
x = 21/2
x = 10.5
48. Solution :- a. 180.6 km
Sides of triangle
L1= 9 cm

L2 = 11 cm
L3 = 13 cm
Shorter distance = 125 km
Shorter length = 9 cm
Longest length = 13 cm
Longest distance = (125 x 13)/9
= 180.555 km
After round off = 180.6 km
49. Solution:- d. $3.81 per lb
0.75-lb package of salami costs = $2.86
Unit price in dollars per pound = 2.86/0.75
= 3.81 per lb
50. Solution:- b. 13/15
Basketball player attempted shots = 15
Basketball player made shots = 13
Ratio = Basketball player made shots/ Basketball player attempted shots
= 13/15
51. Solution :- d. 80%
Percent part = 52/65
= 0.8
In term of percentage = 0.8x100
= 80%

52. Solution:- b. 350%
Percent notation of 3.5
= 3.5x100
= 350%
53. Solution:- c. $17.21
Sales tax rate in one state = 4.25%
1 Chair price = $45
9 Chair price = $45 x9
= $405
Sales tax = $405 x 4.25%
= (405x425)/100
= $17.2125
After Round off = $17.21
54. Solution:- a. $140.00
Principal = $1000
Interest Rate = 2%
Time in years = 7
Simple interest = (Principal x Interest Rate x Time)/100
Simple interest = (1000x 2x 7)/100
Simple interest =14000/100
Simple interest = $140.00
55. Solution:- c. 1/10
Fraction notation = 10/100