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Quality Systems Design | Assignment

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Added on  2020-03-16

Quality Systems Design | Assignment

   Added on 2020-03-16

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Quality Systems DesignNameUniversity8th October 2017
Quality Systems Design | Assignment_1
Question 1:a)AnswersDescriptive Statistics: Pb1_Workhours Variable Mean StDev Minimum Q1 Median Q3 MaximumPb1_Workhours 122.18 15.89 97.00 111.00 120.00 132.25 162.00The above results shows that the mean is 122.18 while the median is 120. The standarddeviation is 15.89. The values shows that the data is close to normally being distributed.We can therefore say that the data is normally distributed.b)AnswerThe stem and leaf plot below;Stem-and-leaf plot (Pb1_Workhours):Unit:109 7 8 810 0 0 3 5 7 8 9 911 1 1 2 2 2 3 3 4 6 6 7 8 912 0 0 2 2 4 4 4 8 8 813 1 1 1 2 3 3 5 6 8 814 2 615 0 5 816 2The shape and distribution of the stem-and-leaf plot shows that the data is normallydistributed.c)AnswerHistogram
Quality Systems Design | Assignment_2
The histogram above suggest that the data is normally distributedd)AnswersProbability plotPb1_WorkhoursPercent1701601501401301201101009080999590807060504030201051Mean0.291122.2StDev15.89N50AD0.433P-ValueProbabilityPlotofPb1_WorkhoursNormal-95%CI
Quality Systems Design | Assignment_3
Question 2:a)HypothesisThe hypothesis for the given test is;H0:μA=μBHA:μA≠μBThat is;H0: The before is the same as the mean afterHA: The before is not the same as the mean afterb)Interpretation of the p-value;Paired T-Test and CI: Pb2_Before, Pb2_After Paired T for Pb2_Before - Pb2_After N Mean StDev SE MeanPb2_Before 10 5.03200 0.58309 0.18439Pb2_After 10 5.52600 0.44257 0.13995Difference 10 -0.494000 0.881542 0.27876895% CI for mean difference: (-1.124617, 0.136617)T-Test of mean difference = 0 (vs not = 0): T-Value = -1.77 P-Value = 0.110The p-value is given as 0.110 (a value greater than 5% level of significance0, wetherefore fail to reject the null hypothesis and conclude that the mean completiontimes before and after are not significantly different.
Quality Systems Design | Assignment_4

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