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Physics Solved Problems on Force, Gravitational Force, Angular Speed, Specific Heat, Telescope Lens and Spring Constant

   

Added on  2022-10-15

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Ques. 1
(a)

F=3 i+ 4 j
m=2 kg

a=?

F=m a
Where F is force on a body
m is mass of body
And a is acceleration
So,
3 i+ 4 j=2 a
1
2 (3 i+4 j )= a
1.5 i+ 2 j= a
Magnitude is
a= ( 1.5 )2+ ( 2 )2
a=2.5 m/ s2
According to newton’s 2nd law of motion.
The direction is same as direction of force.
So,
tanθ= y
x
tanθ= 2
1.5
tanθ=1.33
θ=tan1 1.33
θ=53.130 ¿ xaxis
Ques.2
(b)
The planet revolve around the sun which have relation between time period (T) and distance
between sun and planet radius (r) (for circular orbits) is
Physics Solved Problems on Force, Gravitational Force, Angular Speed, Specific Heat, Telescope Lens and Spring Constant_1
T 2=r3
Let us consider mass of orbit is m.
And mass of sun is M.
We know that M >>>> m
Radial force is equal to gravitational force
GMm
r2 =m ω2 r
ω2=GM
r3 ..................(1)
T = 2 π
ω
ω= 2 π
T .................(2)
From equation (1) and (2)
(2 π )2
T2 = GM
r3
T 2= 4 π2 r3
GM
So we have that
T 2=r3
Distance of Uranus from earth is 20AU
Distance of Pluto from earth is 40AU
So,
TUranus
2
T Pluto
2 = 203
403
TUranus
2
T Pluto
2 = 8
64 = 1
8
TUranus
2
T Pluto
2 = 1
2 2
Ques. 3
(a)
Physics Solved Problems on Force, Gravitational Force, Angular Speed, Specific Heat, Telescope Lens and Spring Constant_2
Mass = 5kg
Diameter = 0.4m
r = d/2
r = 0.2m
n1=2rev /sec
The angular speed increases 8 revolutions per second in 2sec.
n2 =8 rev /sec
ω=2 πn
ω1=2 π ×2
ω1=4 π
ω2=2 π × 8
ω2=16 π
Angular acceleration ()
= ω2ω1
t
=(16 π 4 π )
2
= 2 π (82)
2
=6 π rad /s2
Moment of inertia of wheel is
I =M r2
I =5 ×0.22
I =0.2 N / m2
Torque ( τ )=I ×
τ =0.2 ×6 π
τ =3.77 Nm
Ques. 4
Physics Solved Problems on Force, Gravitational Force, Angular Speed, Specific Heat, Telescope Lens and Spring Constant_3

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