This document provides solutions to forward contract problems, including calculating the optimal hedge ratio and determining the effective price paid by the company. It includes step-by-step explanations and examples.
Contribute Materials
Your contribution can guide someone’s learning journey. Share your
documents today.
Question 1 (a)F0=¿$928.17, r = 0.04, S0= $980, and q =? F0=S0e(r−q)T=980e (0.01−q)1 928.17=970.25e−q q=ln(970.25 928.17)=0.0443 coupon value = 0.0443 x $1,000 = $44.3. (b)Given T = 6 months =6 12=0.5, r = 0.04, S0= $980, and q = 0.0443 F0=S0e(r−q)T=980e (0.01−0.0443)x0.5=$963.34 (c)The arbitrageur borrows $980 to purchase the bond and short a forward contract. To compute the present value of the first coupon, we discount 44.3e−0.04x3 12=$43.86 The remaining $980 - $43.86 = $936.14 is borrowed at 4% annually for remaining 3 months 936.14e−0.04x3 12=$926.83. The arbitrageur makes $962.28 - $926.83 = $ 35.45 for 3 months. Therefore, the arbitrage strategy is action now and borrow $980 for $43.86 for three months and $936.14 for 3 months. Buy one unit of the asset and enter into forward contract to sell asset in 6 months for $962.28. Next action in three months receive $43.86 of income on asset use $43.86 to repay first loan with interest. Finally, action in 6 months. Sell asset for $962.28 use $926.83 to repay second loan with interest.
Secure Best Marks with AI Grader
Need help grading? Try our AI Grader for instant feedback on your assignments.
Question 2 (a)Here r = 0.01, S0= 1458, T = 1, and q = 2ln(1+0.02 2)= 0.0199. The future price F0is therefore, F0=S0e(r−q)T=1458e(0.01−0.0199)1=1,443.64 (b)F0= 1,432, r = 0.01, T = 1, q = 0.0199, and S0=? 1,432=S0e(0.01−0.0199)1 S0= 1,446.25 = K The value of the contract is f=(F0−K)e−rT=(1,432−1446)e−0.01=−0.010. Therefore, this contract does not contain value its not worth investing in. (c)F0= 1,450, r = 0.01, T = 1, q = 0.0199, and S0=? 1,450=S0e(0.01−0.0199)1 S0= 1,464 = K The value of the contract is f=(F0−K)e−rT=(1,450−1464)e−0.01=−13.86. Therefore, this contract does not contain value it is not worth investing in. Question 3 (a)r = 0.04, T = 1, F0= $14.72, S0=? F0=(S0+U)erT U=2e−rT=2e−0.04=1.922 14.72=(S0+1.922)e0.04 14.72=S0e0.04+2 S0=$12.22spot price. (b)The following are given r = 0.04, T = 0.5, S0= $12.22 and
U=2e−rT=2e−0.04x0.5=1.96 F0=(S0+U)erT=(12.22+1.96)e0.04x0.5=$14.21 (c)Gain $20000 the gain per asset = $20000/10 = $2000/5000 = $0.40 per ounce. Gain = F0– quoted price implying F0= 0.4 + 14.72 = $15.12. Now, r = 0.04, T = 0.25, F0= $15.12, S0=? F0=(S0+U)erT U=2e−rT=2e−0.04x0.25=1.98 15.12=(S0+1.98)e0.04x0.25 15.12=S0e0.04x0.25+2 S0=$12.99spot price. Question 4 (a)The data is as shown in the tale MonthFuture PricesSpot Price 120.7021.40 221.8021.80 320.8021.10 422.0021.70 521.8021.90 622.1022.20 722.4022.30 821.5022.70 922.2022.00 1022.8021.70 1122.0021.60 1221.4021.90 1321.6022.50 1422.5022.40 1522.4022.30 1622.6021.40 1721.3021.80 1822.0022.50 1922.5022.30 2022.4022.70 2122.5022.90 2223.2022.50
2322.5022.70 2423.2022.70 The minimum variance hedge ratio is given as follows: h=ρ.δs δF Where, ρ– correlation between future price and spot price δsandδF– standard deviation of the spot price and future price respectively. From excel,ρ= 0.520259,δs=0.492774andδF=0.648689. h=0.520259x0.492774 0.648689=0.395213 (b)The company should take long contracts. Optimal number of contracts =¿desiredunderlyingportfolio contract¿onefuturecontractxh Optimal contract =125,000 1,000x0.395213=49contracts. (c)The effective price paid by the company is calculated as Price = 21.4 + (23.2 – 20.9) = $23.7