Operations Management Solutions

This operations management assignment provides solutions to various problems. It includes calculations for cycle time based on production rate and time, determining the minimum number of workstations required for a given process, and analyzing different locations for optimal suitability based on factors like material supply, quality of life, climate, and labor skills.

Question and Answer
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Operation Management

Question and Answer
Contents
Solution 1a.......................................................................................................................................3
Solution 1b.......................................................................................................................................3
Solution 1c.......................................................................................................................................4
Solution 2a.......................................................................................................................................5
References........................................................................................................................................6
Solution 1a
As per layout principle,
As given in question,
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Question and Answer
No of products = 40
Given time = 8 hr/Shift = 8* 60 = 480 minutes
We know that cycle time ¿ C= t
r where r = no of product and, t = total time
C = 480/40 = 12 minutes Ans
Solution 1b
As given in question,
Total time taken for All task from A to I = 66 min
As from all task A to I, the minimum no of station should be ¿ ∑ t
C = 66
12 =5.5 ≅ 6 station
Therefore, efficiency can be calculated as ¿ ∑ t
nc where n = minimum no of station
= ¿ 66
6∗12 x 100= 66
72 x 100=91.6667 % Ans
Solution 1c
As per minimum no of station, the process will be configured in this way.
Balance delay at each station In minutes
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Question and Answer
Station (Modified) Task Tim
e
Cycle time delay
T1 A 10 12 =12-10 = 2
T2 B 11 12 =12-11 = 1
T3 C,D,F 12 12 =12-12=0
T4 E 12 12 =12-12=0
T5 G,I 10 12 =12-10=1
T6 H 11 12 =12-11=1
Overall delay in balancing = 100- 91.6667 = 8.333 %
Ans
Solution 2a
As given in question,
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Question and Answer
First I have to calculate the weighted score for all location by the formula = weighted% *
location value. Then I have to calculate the composite score by summing each column, the
highest composite score will have best possible location.
Location
Factor
Weightage Loc. A Loc. B Loc. C Loc. D
Material Supply 10% 5*0.1=0.5 9*0.1=0.9 8*0.1=0.8 7*0.1=0.7
Quality of Life 20% 9*0.2=1.8 8*0.2=1.6 4*0.2=0.8 6*0.2=1.2
Climate 30% 10*0.3=3 6*0.3=1.8 8*0.3=2.4 8*0.3=2.4
Labour Skills 40% 3*0.4=1.2 4*0.4=1.6 7*0.4=2.8 6*0.4=2.4
Score Composite 0.5+1.8+3+1.2
=6.5
0.9+1.6+1.8+1.6=
5.9
0.8+0.8+2.4+2.8
=6.8
0.7+1.2+2.4+2.
4=6.7
From the calculated composite score, the score of location C is highest; therefore,
location C is best possible location
References
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Question and Answer
David Alan Collier, J. R. (2012). Operations Management (2nd ed.). New York: Cengage
Learning.
Robert Jacobs, R. C. (2013). Operations and Supply Chain Management (14th ed.). New York:
McGraw-Hill Higher Education.
Steve Brown, J. R. (2013). Strategic Operations Management (3rd ed.). New York: Routledge.
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