Question and Answer1 | P a g eOperation Management
Question and AnswerContentsSolution 1a.......................................................................................................................................3Solution 1b.......................................................................................................................................3Solution 1c.......................................................................................................................................4Solution 2a.......................................................................................................................................5References........................................................................................................................................62 | P a g e
Question and AnswerSolution 1a As per layout principle,As given in question,No of products = 40Given time= 8 hr/Shift = 8* 60 = 480 minutesWe know that cycle time ¿C=tr where r = no of product and, t = total timeC = 480/40 = 12 minutesAnsSolution 1bAs given in question,Total time taken for All task from A to I = 66 minAs from all task A to I, the minimum no of station should be ¿∑tC=6612=5.5≅6stationTherefore, efficiency can be calculated as ¿∑tncwhere n = minimum no of station= ¿666∗12x100=6672x100=91.6667%Ans3 | P a g e
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