Data Communication Question Answer 2022

Running head: DATA COMMUNICATION
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Data Communication
Name of the Student:
Name of the University:
Author Note

1DATA COMMUNICATION
Answer to question number 1
It is given that the queuing, propagation delays, and processing delays are to be ignored
and hence they are considered 0. Length = L, the transmission rates are R1, R2, R3.
Hence the total end to end delay = L (1/R1 + 1/R2 + 1/R3)
Answer to question number 2
Part a
It is given that,
Length = 1,000 bytes
Transmission Rate = 10 Mbps
Distance =1,200 km
Speed = 2.4 x 10^8 m/s
Transmission delay = (1000 bytes * 8 bytes/bit) / ( 10 Mbps * 1000000 bps/Mbps ) = 0.0008 s =
0.8 ms
Propagation delay = (1200 km * 1000 m/km) / (2.4 * 10^8 m/s) = 0.005 s = 5.0 ms
Therefore total delay = Transmission delay + Propagation delay = 5.8 ms

2DATA COMMUNICATION
Part b
The total time = (L/R) + (d/s)
Part c
Length = 1 bytes
Transmission Rate = 10 Mbps
Distance =1,200 km
Speed = 2.4 x 10^8 m/s
Transmission delay = (1 bytes * 8 bytes/bit) / ( 10 Mbps * 1000000 bps/Mbps ) = 0.0000008 s =
0.0008 ms
Propagation delay = (1200 km * 1000 m/km) / (2.4 * 10^8 m/s) = 0.005 s = 5.0 ms
Therefore total delay = Transmission delay + Propagation delay = 5.0008 ms
Part d
It takes 0.8 ms for the last bit of the packet to be put on the link.
Answer to question number 3
Part a
Given that, R1 = 500 KBs
R2=1.5Mbps, and R3=1Mbps
Therefore, R1 <R3 < R2
Therefore, the throughput is 200 Kbps.

3DATA COMMUNICATION
Part b
((50MB * 1000000B/MB)*8 B/b) / (500 kbps * 1000 bps/kbps)
= 800 seconds
Answer to question number 4
Part a
Link = 2Mbps or 2000 kbps
Bandwidth = 500 kbps
Therefore, the number of users for the network = 2000/500 = 4.
Part b
Probability that a giving user is transmitting = 0.1
Part c
Probability for single user = 0.1
Therefore, the probability for 5 users = (1/10) ^ 5 = 0.00001
Answer to question number 5
The port number of the socket in the destination process and the IP address of the
destination host are used by a process running on one host to identify a process running.
Answer to question number 6
Part a
False. Different objects have their own request message and response message.