The Ration of Moles of HC7H5O3 to HC9H7O4 Moles

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Added on 2020-05-16

The Ration of Moles of HC7H5O3 to HC9H7O4 Moles

Added on 2020-05-16

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The Ration of Moles of HC7H5O3 to HC9H7O4 Moles_1

Lab reportsTitle: Synthesis of Aspirin (Acetylsalicylic acid).Introduction This experiment involves production of aspirin. The major reactants which were used in the experiment include salicylic acid HC7H5O3, and C4H6O3.The reactants reacted in order to produceacetylsalicylic acid or simply aspirin HC9H7O4and ethanol acid CH3CHOOH. Asprin has several uses such as an analgesic or painkiller, as an anti-pyretic or fever reducer and as thinning of the blood. Balanced equation HC7H5O3 + C4H6O3 = HC9H7O4 + CH3CHOOHMoles ratio 1111= Results and Calculation Available results:Salicylic acid mass= 3.2888 gExperiment yield of Aspirin: =3.625gAcetic Acid Anhydride density:1.1 g/mLAcetic acid anhydride volume: 10mLMoles of salicylic acid:

The Ration of Moles of HC7H5O3 to HC9H7O4 Moles_2

HC7H5O3 Molar mass = 138g/mol as givennumber of moles = HC7H5O3 grams/ HC7H5O3 molar massMoles =3.2888g/138g/mol= 0.0238319 molesAcetic acid anhydride moles:C4H6O3 Molar mass =102g/molAcetic acid density=1.1g/mLMass = density times volumeacetic acid anhydride mass=1.1g/mL × 10mL=11number of moles =grams/molar massAcetic acid anhydride Moles =11g/102g/mol=0.1078431molesLimiting reagent In this case, the limiting reagent was found using the moles ratio indicated as the ration of Salicylic acid moles to acetic acid molesFrom the equation, the mole ration is 1:1Therefore, theoretically, 1 mole of acetic acid anhydride = 1 mole of salicylic acid. This means that the moles for salicylic acid will be 0.0238319 theoretically.

The Ration of Moles of HC7H5O3 to HC9H7O4 Moles_3

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Synthesis of Aspirin

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The Ration of Moles of HC7H5O3 to HC9H7O4 Moles