2BIOSTATISTICS ANSWER 1 The difference in proportion between men and women illicit drug users is 0.06 in 2001. The 95% confidence interval for difference in mean is -0.07 and 0.19. The 95% confidence interval of the difference in proportion can be interpreted as when another sample is taken then there is 95% probability that the proportion of illicit drug users would lie between -0.07 and 0.19. In other words, there is a 95% probability that the difference in the proportion of illicit drug users for men and women is between 0.0 and 0.19. Moreover, there is 95% probability that the difference in proportion ofillicit drug users for women and men is between 0.0 and 0.07. ANSWER 2 For men in 2016 the proportion of illicit drug users is 0.24 or 24%. The 95% confidence interval for illicit drugs users, men is between 0.15 and 0.33. Hence, there has been a reduction in illicit drug users from 2001 to 2016 below 0.35. In addition, it can also be stated that there is 5% probability that the proportion of illicit drugs is above 0.33.
3BIOSTATISTICS For women, the proportion of illicit drugs in 2016 is 0.29 or 29%. The 95% confidence interval for illicit drugs users, women is between 0.20 and 0.38. Thus, there is a 95% probability that the proportion of a women being illicit drug user is above 0.35. ANSWER 3 The mean proportion of calories coming from dietary fat for the intervention group is 0.202. Further, the 95% confidence interval of the proportion of calories coming from dietary fat for the intervention group lies between 0.170 and 0.235. The 95% confidence interval can be interpreted that when another study is undertaken then there is a 95% probability that the mean proportion of calories coming from dietary fat would lie between 0.170 and 0.235.
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4BIOSTATISTICS In the following investigation binomial probability is used. There are only two groups. Since, a subject can be in either of one group, hence it is a binomial probability. ANSWER 4 The mean proportion of calories from dietary fat for intervention group is 0.202. Moreover, the 95% probability of the mean proportion of calories from dietary fat lies between 0.170 and 0.235. Thus, it can be inferred that there is a 95% probability that the mean would be less than 0.235 or 23.5%. Thus, there is a 95% evidence that the mean for the intervention group lie’s below 35%. ANSWER 5 In order to analyze for differences in mean proportion of dietary fat independent sample t-test is used. The hypothesis for analyzing the difference in the mean proportion of dietary fat between the control and intervention group can be formulated as: Null hypothesis: There is no difference between the mean proportion of dietary fat between control and intervention group. H0:μcontrol=μintervention Alternate hypothesis: There are differences between the mean proportion of dietary fat between control and intervention group. HA:μcontrol≠μintervention
5BIOSTATISTICS From the test it is found that at 0.05 level of significance there are significant differences in the mean proportion of dietary fat of control and intervention group, p < 0.000. The mean proportion of dietary fat of control group (0.3414815) is found to be higher than for intervention group (0.2024828). ANSWER 6 From the results it can be seen that the mean of the score is 35.46. The 95% confidence interval is 31.57, 39.36. The 95% confidence interval can be interpreted as when a similar score of the 80 students is taken then there is a 95% probability of the mean score to be between 31.57 and 39.36.