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SOIL MECHANICS

[Author Name(s), First M. Last, Omit Titles and Degrees]

[Institutional Affiliation(s)]

QUESTION ONE

The Brock Commons house has just been viewed as the tallest wood building in the North

America. The structure is 13-story that is found in the Pointe-aux-Lièvre's eco-neighborhood in the

city of Quebec. The tall strong timber structure has been developed on the platform made of

cement. The structure is 134 feet in its stature. The structure is special by the way that it is

comprised of totally the strong wood. The wooden structure is found in the staircases and

furthermore in the poles of the lift.

The outside walls and the cross are likewise made of the wooden segments. The structure is a mix

of the glulam bars and sections and furthermore the CLT segments. The shot which has been made

by the new, bigger and the taller building made of wood has been perceived as a choice which is

feasible in the nation particularly by the building and the construction network(Poirier et al 2016).

The procedure has been made conceivable by the advancement of the results of the forested areas.

The methodology and the reasoning of the whole project was essentially to utilize the materials in

the most prescribed way which took into account accomplishment of the cross breed arrangement

of solid characteristics and timber.

QUESTION TWO

The various loads on the floors selected for the study

Timber

FactorsSolution

Temperature

Timber tends to become much stiffer and

brittle when exposed to very high temperature.

This normally results into the twisting effects.

The construction of the Brock building has

used technique of allowance provision to

compensate for the effects of the twisting.

Moisture

The quality of timber is lowered when it is

excessively exposed to the moist environment.

The timber will actually rot.

The construction has used water proof material

at the foundation to limit the access of water to

the building.

The Brock Commons house has just been viewed as the tallest wood building in the North

America. The structure is 13-story that is found in the Pointe-aux-Lièvre's eco-neighborhood in the

city of Quebec. The tall strong timber structure has been developed on the platform made of

cement. The structure is 134 feet in its stature. The structure is special by the way that it is

comprised of totally the strong wood. The wooden structure is found in the staircases and

furthermore in the poles of the lift.

The outside walls and the cross are likewise made of the wooden segments. The structure is a mix

of the glulam bars and sections and furthermore the CLT segments. The shot which has been made

by the new, bigger and the taller building made of wood has been perceived as a choice which is

feasible in the nation particularly by the building and the construction network(Poirier et al 2016).

The procedure has been made conceivable by the advancement of the results of the forested areas.

The methodology and the reasoning of the whole project was essentially to utilize the materials in

the most prescribed way which took into account accomplishment of the cross breed arrangement

of solid characteristics and timber.

QUESTION TWO

The various loads on the floors selected for the study

Timber

FactorsSolution

Temperature

Timber tends to become much stiffer and

brittle when exposed to very high temperature.

This normally results into the twisting effects.

The construction of the Brock building has

used technique of allowance provision to

compensate for the effects of the twisting.

Moisture

The quality of timber is lowered when it is

excessively exposed to the moist environment.

The timber will actually rot.

The construction has used water proof material

at the foundation to limit the access of water to

the building.

C

Concrete

Water/cement ratio

The construction of the foundation of the

building has been done using concrete whose

performance is normally affected by the water/

cement ratio.

The construction of the structure has employed

the right ratio of water /cement so as to

improve on the durability of the building.

Moisture exposure

The concrete is normally affected in terms of

the performance when it is exposed to too

much moisture content.

Use of plastic material that is water proof to

limit the moisture exposure

Steel

Moisture

Steel is capable of undergoing rusting when it

is excessively exposed to lots of moisture.

The steel has been reinforced within the

concrete to limit the exposure to moisture.

Expansion and contraction

The metal will need some allowance due to

temperature change for expansion and

contraction to take place

The construction process has allowed room for

the variation of length of the steel due to

changes in the temperature.

Concrete

Water/cement ratio

The construction of the foundation of the

building has been done using concrete whose

performance is normally affected by the water/

cement ratio.

The construction of the structure has employed

the right ratio of water /cement so as to

improve on the durability of the building.

Moisture exposure

The concrete is normally affected in terms of

the performance when it is exposed to too

much moisture content.

Use of plastic material that is water proof to

limit the moisture exposure

Steel

Moisture

Steel is capable of undergoing rusting when it

is excessively exposed to lots of moisture.

The steel has been reinforced within the

concrete to limit the exposure to moisture.

Expansion and contraction

The metal will need some allowance due to

temperature change for expansion and

contraction to take place

The construction process has allowed room for

the variation of length of the steel due to

changes in the temperature.

Figure 1: The dead loads are actually acting downwards (Zhuo 2016).

Figure 2: Dead loads acting from the roof system (Zhuo 2016).

Figure 3: Dead loads acting on the floors downwards (Zhuo 2016).

Figure 2: Dead loads acting from the roof system (Zhuo 2016).

Figure 3: Dead loads acting on the floors downwards (Zhuo 2016).

QUESTION THREE

1st Storey:

Dead Load:

What is assumed: The calculation that has been done is on the assumption that the floor is

suspended.

Floor system = 0.75 kPa (assumed) x (6/2 + 4/2) x (5.6/2 + 4.4/2) = 18.75 kN Column

= 0.45 x 0.4 x 4.75x 24 =20.52 kN

Wall unit = 20 x 0.175 x (6/2 +4/2) x 4.75 =83.13 kN

Total= 121.4kN

SecondStorey:

Dead Load:

Floor = 0.15m (assumed) x 24 x (6/2 + 4/2) x (5.6/2 + 4.4/2) =90kN Floor

system = 0.75 kPa (assumed) x (6/2 + 4/2) x (5.6/2 + 4.4/2)= 18.75 kN Column =

0.45 x 0.4 x 3.46 x 24 =15 kN wall system = 20

x 0.175 x (6/2 + 4/2) x (5.6/2 + 4.4/2) =60.55 main Beam = 24 x 0.6m

x 0.8m x (6/2 + 4/2) =57.6 kN

Supporting beam = 24 x 0.25 x 0.45 x (6/2+ 4/2) =13.5 kN

Total = 256.4 kN

Live Load:

1st Storey:

Dead Load:

What is assumed: The calculation that has been done is on the assumption that the floor is

suspended.

Floor system = 0.75 kPa (assumed) x (6/2 + 4/2) x (5.6/2 + 4.4/2) = 18.75 kN Column

= 0.45 x 0.4 x 4.75x 24 =20.52 kN

Wall unit = 20 x 0.175 x (6/2 +4/2) x 4.75 =83.13 kN

Total= 121.4kN

SecondStorey:

Dead Load:

Floor = 0.15m (assumed) x 24 x (6/2 + 4/2) x (5.6/2 + 4.4/2) =90kN Floor

system = 0.75 kPa (assumed) x (6/2 + 4/2) x (5.6/2 + 4.4/2)= 18.75 kN Column =

0.45 x 0.4 x 3.46 x 24 =15 kN wall system = 20

x 0.175 x (6/2 + 4/2) x (5.6/2 + 4.4/2) =60.55 main Beam = 24 x 0.6m

x 0.8m x (6/2 + 4/2) =57.6 kN

Supporting beam = 24 x 0.25 x 0.45 x (6/2+ 4/2) =13.5 kN

Total = 256.4 kN

Live Load:

LL = 4 KN//m2(assumed) x (6/2 + 4/2) x (5.6/2 + 4.4/2) =100 kN

Second upper or Third storey

(i) Dead Load:

System Slab = 0.15m (assumed) x 24 x (6/2+ 4/2) x (5.6/2) =51.4 kN

Beam = 24 x 0.6m x 0.8m x 6=68.1 KN

Floor system = 0.75 kPa (assumed) x (6/2 + 4/2) x(5.6/2) =10.5kN

Vertical Column = 0.45 x 0.4 x 3.06 x 24 =12.22 kN

wall system = 20 x 0.175 x (6/2 + 4/2) x 3.06 =54.55 kN

Total = 197.77 kN

(ii) Live Load: (2ndUpper StoreyRooms)

LL = 4 KN/m2(assumed) x (6/2 + 4/2) x (5.6/2) =50 kN

(2d)Roof Level:

Wall unit = 20 x 0.175 x 1.81 x (6/2+ 4/2) =32 kN Dead Load service

= 0.75 kPa (assumed) x (5.6/2 + 4.4/2) x (6/2 + 4/2) =18.75 kN

Total =53.75 kN

Second upper or Third storey

(i) Dead Load:

System Slab = 0.15m (assumed) x 24 x (6/2+ 4/2) x (5.6/2) =51.4 kN

Beam = 24 x 0.6m x 0.8m x 6=68.1 KN

Floor system = 0.75 kPa (assumed) x (6/2 + 4/2) x(5.6/2) =10.5kN

Vertical Column = 0.45 x 0.4 x 3.06 x 24 =12.22 kN

wall system = 20 x 0.175 x (6/2 + 4/2) x 3.06 =54.55 kN

Total = 197.77 kN

(ii) Live Load: (2ndUpper StoreyRooms)

LL = 4 KN/m2(assumed) x (6/2 + 4/2) x (5.6/2) =50 kN

(2d)Roof Level:

Wall unit = 20 x 0.175 x 1.81 x (6/2+ 4/2) =32 kN Dead Load service

= 0.75 kPa (assumed) x (5.6/2 + 4.4/2) x (6/2 + 4/2) =18.75 kN

Total =53.75 kN

Dead Loads of roof = 0.75KN/m2x5 x5=14.17

Roof Materials kN = 1.5KN//m2x5 x5 =57.25 KN

Addition of Dead Load = 122.4 + 255.4 + 197.77 + 51.75 + 56.25 =682.57 kN

Base strip Size of 2m width (instead of 4m) x 4m (range Length) x .75mm thick

Loads on the Ground Footing Foundation= 24.0 x 2 x 4 x .75 =145.0 KN

Pressure force on the soil = 989.64 / (2.0 x 4.0) = 124.71 KN//m2

4 Plan for live loads

Roof Materials kN = 1.5KN//m2x5 x5 =57.25 KN

Addition of Dead Load = 122.4 + 255.4 + 197.77 + 51.75 + 56.25 =682.57 kN

Base strip Size of 2m width (instead of 4m) x 4m (range Length) x .75mm thick

Loads on the Ground Footing Foundation= 24.0 x 2 x 4 x .75 =145.0 KN

Pressure force on the soil = 989.64 / (2.0 x 4.0) = 124.71 KN//m2

4 Plan for live loads

5. Dynamic load calculation

Taking into account the height of the building that has been assumed to be 4.4m ,the

multiplication thus becomes 4.4*maximum number of floors

A=W*L

4.4*0.5*1/12

=0.125ft2 but P=0.00256*V2

=70*70*0.00256;12.5

The value of the coefficient is equivalent to 0.8; therefore F=0.125*12.5*0.8=1.25.

6 Durability

Steel is typically influenced by the procedure of the corrosion. This can be

controlled by the utilization of the galvanic erosion insurance. The solid might be

Taking into account the height of the building that has been assumed to be 4.4m ,the

multiplication thus becomes 4.4*maximum number of floors

A=W*L

4.4*0.5*1/12

=0.125ft2 but P=0.00256*V2

=70*70*0.00256;12.5

The value of the coefficient is equivalent to 0.8; therefore F=0.125*12.5*0.8=1.25.

6 Durability

Steel is typically influenced by the procedure of the corrosion. This can be

controlled by the utilization of the galvanic erosion insurance. The solid might be

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