Area of Parallelogram, Triangle, Rectangle, Cuboid, Swimming Pool

Solution (1):
Given figure is a parallelogram whose base is 40 ft. and height is 20ft.
Area of parallelogram = base x height = 40 x 20 = 800 ft2
Solution (2):
Given figure is a triangle whose base length is 0.5 m + 0.8 m = 1.3 m and height is
1.2 m
Area of parallelogram = (1/2) x base x height = (1/2) x 1.3 x 1.2 = 1.56/2 = 0.78 m2
Solution (3):
In given figure 2 rectangles are there, first is ABGF and second is EGCD.
Area of rectangle = length x width
Area of rectangle ABGF = (18 + 7) x 12 = 25 x 12 = 300 in2
Area of rectangle EGCD = (32 – 12) x 7 = 20 x 7 = 140 in2
Area of figure = 300 + 140 = 440 in2