Solutions for Order number 1022789

Solutions for Order number 1022789.
1. a. Formula:- V(CO3)2
Molar Mass: V+2(C+O+O+O)
= (51+2(12+16+16+16)
=171g/mol
b. Formula: - S6N8
Molar Mass: 6(S) +8(N)
= {(6*32) + 8(14)}
= 304g/mol
c. Formula:- Be3P2
Molar Mas: 3(Be) +2(P)
= {(3*9) + 2(31)
= 89g/mol
2. Structure for Bisphenol A
(CH3)2C (C6H4OH)2
Or
C15H16O2
Mean that in 1gram there are 15 carbon atoms
1 ton = 907.19kg
2.8tons=? kg
= (2.8*907.19) kg
= 2540.132kg
1kg=1000g
2540.132kg=? g
= (1000*2540.132)
=2540132g

2. In 1g there are 15Carbons
2540132g=? C
= (2540132*15)
= 38101980 Carbon Atoms.
3. Structure for Methionine
C3H7S
a. Percentage of Sulphur
= Total Molar mass {2(C) + 7(H) +S}
=2(12) +7(1) + 32
=64g/mol
% S = Molar mass of S divided by Total mass of Compound multiply by 100
= 32/64*100
=50% of S
b. 458g of Acetic CH3COOH
=C2H4O2
Molar mass = 2(C) + 4(H) + 2(O)
={(2*12) + (4*1) + 2(16)}
=60g/mol.
In 60g of C2H4O2 4there are 4g of Hydrogen
458g =? H
(458g * 4)/60g
=30.5 grams of Hydrogen