Question 1 Part a (i)It would be ordinal since data is categorical and can be arranged in an order. (ii)Ratio level data since numerical data with defined zero. (iii)Nominal level data since categorical values without any automatic arrangement. Part b Cluster sampling Part c The population is all primary school children while the sample is 2350 school children who have been selected Part d i)This is a parameter since it describes the characteristic of a population ii)This is a statistic since it describes the characteristic of a sample. Question 2 Part a (i)Median age would be (17+1)/2 or 9thvalue Based on the given stem and leaf plot, this value is 37 years. The modal age is 35 years since this is the only value which is repeated twice. All the other values have frequency 1. (ii)Maximum value = 60 years Minimum value = 23 years Range = 60 -23 = 37 years 1
(iii)Mean will be impacted since 60 is the largest value in the given data set and thus the new mean would be lower than the current mean. Mode and median would remain unaffected. Part b (i)15 minutes (ii)Since 20 minutes corresponds to 75 percentile of the female data, hence 75% of the females completed their test within 20 minutes (iii)The distribution is asymmetric as the difference between median and Q1 is significantly greater than the difference between median and Q3. This implies that a right skew or positive skew is present. (iv)Option D Question 3 (i)Sample mean x bar= (115+94+61+58+57+53)/2=73 (ii)Table x(X- xbar)(X- x bar)^2 115421764 9421441 61-12144 58-15225 57-16256 53-20400 (iii)Sample variance and sample standard deviation Samplevariances2=(25.4)2=646 Samplestandarddeviations=√∑¿¿¿¿¿ Question 4 2
(a)Classes = 6 Min value = 37 Max value = 95 Class width = (95-37)/6 = 9.66 which means 10 Class width = 10 (b)Table Class limits Frequenc y Class boundaries Class midpoint Cumulative Frequency Relative Frequency 37-46441.540.11 47-5664750.5100.17 57-6695761.5190.25 67-7654771.5240.14 77-8675781.5310.19 87-9654791.5360.14 Total362553981241 (c)Frequency histogram 37-4647-5657-6667-7677-8687-96 0 1 2 3 4 5 6 7 8 9 10 4 6 9 5 7 5 Frequency histogram (Final exam scores%) FInal exam scores % Frequency 3
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Question 5 Part a Weighted average marks = 82*(0.15) + 75*(0.15) +81*(0.15) + 90*(0.15) + 84*(0.10) + 88*(0.30) = 84% Since, average is less than 85%, hence I did not get A+. Part b (i)Coefficient of variation for sales = Standard deviation of sales/Mean of sales = 6/85 = 0.071 Coefficient of variation for commission = Standard deviation of commission/Mean of commission = (720/5350) = 0.135 (ii)Commissions are more variable since the coefficient of variable for it is higher than the corresponding value for sales. 4