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Statistics Assignment | Central Tendency Measures

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Added on  2020-04-01

Statistics Assignment | Central Tendency Measures

   Added on 2020-04-01

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StatisticsNameInstitutionInstructor26th September 20171
Statistics Assignment | Central Tendency Measures_1
Question 1: Below are five questions from a survey of MBA students. Answers were written in the blank at the left of each question. For each question, state the data type (categorical, discrete numerical, or continuous numerical) and measurement level (nominal, ordinal, interval, ratio). Explain your reasoning. If there is doubt, discuss the alternatives.1.What is your gender? (Male = 0, Female = 1)SolutionData TypeMeasurement levelCategoricalNominal2.What is your approximate undergraduate college GPA? (1.0 to 4.0)SolutionData TypeMeasurement levelContinuous numericalInterval3.About how many hours per week do you expect to work at an outside job this semester?SolutionData TypeMeasurement levelContinuous numericalRatio4.What do you think is the ideal number of children for a married couple?SolutionData TypeMeasurement levelDiscrete numericalInterval5.On a 1 to 5 scale, which best describes your parents? (1 = Mother clearly dominant ⟷ 5 = Father clearly dominant)SolutionData TypeMeasurement levelDiscrete numericalOrdinal2
Statistics Assignment | Central Tendency Measures_2
Question 2: Below are monthly rents paid by 30 students who live off campus. (a) Find the mean, median, and mode. (b)Do the measures of central tendency agree? Explain. (c) Calculate the standard deviation. (d) Sort andstandardize the data. (e) Are there outliers or unusual data values? (f) Using the Empirical Rule, do you thinkthe data could be from a normal population?730 7307309307005706901,030740620720670560 740650660850930600 620760690710500730 800820840720700(a)Find the mean, median, and mode.SolutionMean=∑xin=2174030=724.6667Median=15thvalue+16thvalue2=720+7202=720Mode=Mostfrequent=730(b)Do the measures of central tendency agree?SolutionYes the measures of central tendency agree; there is no much variation between the three values(c)Calculate the standard deviationSolutionStandarddeviation=√∑(xi− ́x)2n−1=√378746.729=√13060.23=114.2814(d)Sort and standardize the data. Solution3
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