This article covers topics related to statistics for business decisions such as frequency distribution, ANOVA, regression analysis, and more. It includes tables and graphs to explain the concepts and provides suggestions based on the analysis. The article also mentions relevant textbooks for further reading.
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Statistics for Business Decisions
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Answer 1 a.The frequency distribution tables were constructed in MS Excel and have been provided below. Table1: Frequency Distribution of Examination Scores CLASS INTERVAL LOWER BOUND UPPPER BOUND CLASS MID- POINTFREQUENCY 50-60505954.53 60-70606964.52 70-80707974.55 80-90808984.54 90-100909994.56 Table2: Cumulative Frequency Distribution of Examination Scores CLASS INTERVAL LOWER BOUND UPPPER BOUND CLASS MID- POINTFREQUENCY CUMULATIVE FREQUENCY 50-60505954.533 60-70606964.525 70-80707974.5510 80-90808984.5414 90-100909994.5620
Table3: Relative Frequency Distribution of Examination Scores CLASS INTERVAL LOWER BOUND UPPPER BOUND CLASS MID- POINT FREQUENC Y RELATIVE FREQUENCY 50-60505954.530.15 60-70606964.520.10 70-80707974.550.25 80-90808984.540.20 90-100909994.560.30 Table4: Cumulative Relative Frequency Distribution of Examination Scores CLASS INTERVAL LOWER BOUND UPPPER BOUND CLASS MID- POINT FREQU ENCY RELATIVE FREQUENCY CUMULATIVE RELATIVE FREQUENCY 50-60505954.530.150.15 60-70606964.520.100.25 70-80707974.550.250.50 80-90808984.540.200.70 90-100909994.560.301.00 Table5: Percent Frequency Distribution of Examination Scores CLASS INTERVAL LOWER BOUND UPPPER BOUND CLASS MID- POINT FREQUENC Y PERCENT FREQUENCY 50-60505954.5315.00% 60-70606964.5210.00% 70-80707974.5525.00% 80-90808984.5420.00% 90-100909994.5630.00%
b.From percentage distribution of students based on their examination scores revealed that the nature of the histogram (percentage distribution graph). Accumulation of most of the students was observed above examination score of 70. Left skewness was evident from the shape of the histogram (Black, 2009). It can be inferred that students are getting very good marks in examination. Figure1: Percentage Distribution of Examination Scores
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Answer 2 a.It is known that the “degrees of freedom” of residual in a regression model is taken as (n-p-1), where p is the degrees of freedom of the regression model. Heren−p−1=39,p=1, so the value of n (sample size) is calculated as 41. b.The margin of error at 5% level of significance is1.96∗0.021=0.041and the confidence interval of the slope is [0.029 – 0.041, 0.029 + 0.041] = [-0.012, 0.07]. The standard error of the slope indicates that the values of supply are very closely accumulated around the regression line of X, unit price (in thousands of dollars). c.The given regression table is incomplete, where the values of SS for regression model and residue are provided. Now coefficient of determinant is known asR2=SSM/SST, where SST =SSE+SSM=7389.951.Hence,coefficientofdeterminantiscalculatedtobe R2=7035.262 7389.951=0.952. This implies that 95.2% variation of supply (Y) is explained by the unit price (X).
d.Coefficient of correlationR=√0.952=0.976implies that the supply (Y) and unit price (X) are positively correlated. The value of the correlation indicated a steep increase in supply for change in unit price. e.The regression equation isSupply=0.029∗UnitPrice+54.076 NowforUnitPrice=$50,000,thedependentvariableiscalculatedas Supply=0.029∗50.00+54.076=55.53(inthousandsofunits).Hencepredictedsupplyis approximately 55,530 units (Black, 2011).
Answer 3 a.The ANOVA table is given in table 6 (constructed in MS Excel). Table6: ANOVA for programs in Allied Corporation ANOVA: Single Factor GroupsCountSumAverage Varianc e Program A5725145525 Program B5675135425 Program C5950190312.5 Program D5750150637.5 ANOVA Source of VariationSSdfMSFP-valueF crit Between Groups875032916.6666676.14030.00553.2388 Within Groups760016475 Total1635019 b.The suggestion to Allied Corporation was provided based on the ANOVA results. The exploratory analysis shows that average output of day’s work for the C program is the maximum with average value of 190. The inferential analysis of ANOVA established that indeed, the output from C program is significantly (F = 6.14, p < 0.05) greater than that of from other three programs. Allied corporation was suggested to assign all of their employees in program C (Triola, 2013).
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Answer 4 a.The table 7 shows the regression output at 5% level of significance, calculated in Excel. The regressionequationfromthemodelisformedas, Sales=0.01∗Advertisement+41.32*Price+3.6
Table7: Regression Model for Weekly Sales and Price of Competitor’s Product at 5% Level of significance SUMMARY OUTPUT Regression 95% Regression Statistics Multiple R0.8778 R Square0.7706 Adjusted R Square0.6558 Standard Error1.8374 Observations7 ANOVA dfSSMSF Significance F Regression2.000045.3528 22.676 46.71680.0526 Residual4.000013.50433.3761 Total6.000058.8571 Coefficients Standard Errort Stat P- valueLower 95% Upper 95% Intercept3.59764.05220.88780.4248-7.653214.8484 Price41.320013.33743.09810.03634.289678.3505 Advertising0.01320.32760.04040.9697-0.89630.9228
b.The table 8 shows the regression output at 10% level of significance. The model is significant and that is inferred from the significance level (F = 6.72, p = 0.0526) of the model (Montgomery, Peck, and Vining, 2012). Table8: Regression Model for Weekly Sales and Price of Competitor’s Product at 10% Level of significance SUMMARY OUTPUT Regression 90% Regression Statistics Multiple R0.8778 R Square0.7706 Adjusted R Square0.6558 Standard Error1.8374 Observations7 ANOVA dfSSMSF Significance F Regression2.000045.3528 22.676 46.71680.0526 Residual4.000013.50433.3761 Total6.000058.8571 Coefficients Standard Errort Stat P- valueLower 90.0% Upper 90.0% Intercept3.59764.05220.88780.4248-5.041112.2364 Price41.320013.33743.09810.036312.886869.7532 Advertising0.01320.32760.04040.9697-0.68510.7116 c.Individual relation of the independent variables reveal that advertisement expenditure (X2) is not significantly (t = 0.04, p =0.97) related to sales of the product (Y), whereas unit price of the competitors’ (X1) is significantly (t = 3.1, p < 0.1) related to sales of the product (Y) (Cox, and Wermuth, 2014).
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d.The table 9 shows the regression output at 10% level of significance with unit price of competitors’ (X2) as the only variable (Vittinghoff et al., 2011). The new regression equation is calculated asSales=41.60Price+3.582 Table9: Regression Model for Weekly Sales and Price of Competitor’s Product at 10% Level of significance with Single Factor SUMMARY OUTPUT Regression 90% Regression Statistics Multiple R0.8778 R Square0.7705 Adjusted R Square0.7246 Standard Error1.6438 Observations7 ANOVA dfSSMSF Significance F Regression1.000045.3473 45.347 3 16.783 10.0094 Residual5.000013.50982.7020 Total6.000058.8571 Coefficients Standard Errort StatP-valueLower 90.0% Upper 90.0% Intercept3.58183.60820.99270.3664-3.688910.8525 Price41.603110.15524.09670.009421.139862.0663 e.Slope of the independent variable, unit price of competitors’ (X2) is 41.60 (t = 4.09, p < 0.05) that indicates existence of a positive correlation with the sales of the products (Y). Hence, from regression equation it can be said that sales of product (Y) increases by 41.60 units for one unit increase in competitors’ price of products (Burns, Bush, and Sinha, 2014).
References Black, K., 2009.Business statistics: Contemporary decision making. John Wiley & Sons. Black, K., 2011.Business statistics: for contemporary decision making. John Wiley & Sons. Burns, A.C., Bush, R.F. and Sinha, N., 2014.Marketing research(Vol. 7). Harlow: Pearson. Cox,D.R.andWermuth,N.,2014.Multivariatedependencies:Models,analysisand interpretation. Chapman and Hall/CRC. Montgomery, D.C., Peck, E.A. and Vining, G.G., 2012.Introduction to linear regression analysis(Vol. 821). John Wiley & Sons. Triola, M.F., 2013.Elementary statistics using Excel. Pearson. Vittinghoff, E., Glidden, D.V., Shiboski, S.C. and McCulloch, C.E., 2011.Regression methods in biostatistics: linear, logistic, survival, and repeated measures models. Springer Science & Business Media.