Added on - 15 May 2020

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Running head: STATISTICSStatisticsName of the studentName of the universityAuthor’s note
STATISTICS2Answer 1SourceDFSSMSFFactorm-1SS (Between)MSB =SS(Between)/(m-1)MSB/MSEErrorn-mSS (Error)MSE = SS(Error)/(n-m)Totaln-1SS (Total)Part aTable 1: ANOVA tableSource of VariationSum of SquaresDegrees of FreedomMean SquareFBetween Treatments903305Within Treatments (Error)120206Total21023From excel we find that p-value for F= 5 at 3,20dfis 0.0095. Since, p-value <-valuehence reject Null Hypothesis.Part bdffor number of groups:m-1 = 3m = 3 + 1 = 4Hence, number of groups = 4Part cTotal number of observationsn – 1 = 20n = 21Hence, number of observations = 21
STATISTICS3Answer 2Table 2: Coefficients of Regression EquationCoefficientsStandardErrort StatP-valueIntercept136.000013.76319.88150.0000Year(t)39.18182.218117.66430.0000The linear trend equationNumber of Units sold (000s) = 136.00 + 39.1818*Year (t)The number of cars sold for t = 11Number of Units sold (000s) = 136.00 + 39.1818*Year (t)Number of Units sold (000s) = 136.00 + 39.1818*11Number of Units sold (000s) = 136.00 + 430.9998Number of Units sold (000s) = 566.9998 ≈ 567From the sales trend it is seen that the sales in the 11thyear would be 567 (000s)

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