Statistics Of A Student Evaluation

STATISTI
CS
[DATE]
[COMPANY NAME]
[Company address]

Question 1
Sample size = 200
Number of students received grades more than ‘B’= 112
Significance level = 10%
Claim: More than 50% students received grades better than “B”
A) Null and alternative hypothesis
H0 :π =0. 50
Ha :π > 0.50
B) Z critical value
Alpha (Significance level) = 0.10
It is a right tailed hypothesis test based on the alternative hypothesis.
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Decision rule: Null hypothesis will only be rejected when the computed z statistics is more
than z critical.
C) The sample proportion and z statistics
p= 112
200 =0.56
z statistics= p−π
√ ( π 1−π
n ) = 0.56−0.5
√ ( 0.5∗1−0.5
200 ) =1.6971
D) The p value
E) Conclusion
P value does not come out to be higher than the provided significance level and hence, null
hypothesis would be rejected. Also, the z statistics is more than the z critical which is
evidence of rejection of null hypothesis.
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