Structure and Function of Biomolecules and Genetic Expression
Verified
Added on  2023/05/31
|9
|2244
|122
AI Summary
This report discusses the structure and function of biomolecules and genetic expression, including the basic features of amines, esters, and amides, and the mechanisms of DNA and RNA processes in an organism. It also covers the classification of carbohydrates and the components of the cell membrane.
Contribute Materials
Your contribution can guide someone’s learning journey. Share your
documents today.
Running head: REPORT1 Report Student’s Name University Affiliation
Secure Best Marks with AI Grader
Need help grading? Try our AI Grader for instant feedback on your assignments.
REPORT2 Questions and Answers Introduction The report involves questions and answers that discuss the structure and function of biomolecules and identifies the basic features of amines, esters, and amides. The report also discusses genetic expression and the mechanisms of DNA and RNA process in an organism. PART A Question One Both hexamine and triethylamine have the same number of electrons and molecular weight but their boiling point varies because of their differences in intermolecular hydrogen bonding. Hexamine has higher boiling points than triethylamine because it has hydrogen bonds as well as van der Waals dispersion forces whereas triethylamine has not. Question Two The boiling point of propanol is higher than that of propanal. The main reasons for this variation are as a result of their differences in intermolecular forces and polarization. Propanal is an aldehyde which has Oxygen which is highly polar and has no hydrogen bonds (Nelson, Cox, & Lehninge, 2005). It has only dipole-dipole interactions which are weak intermolecular force whereas propanol which is an alcohol has hydrogen bonds which have the strongest intermolecular forces acting between hydrogen molecules thus their variation in their boiling points. Question Three Both stearic and linoleic acid are all carboxylic acids with 18 carbon atoms but have differences in their melting points. Their large differences in melting point are as a result of the saturation. Stearic fatty acid is saturated fatty acid whereas linoleic acid is unsaturated fatty acid. The higher the unsaturation, this is why linoleic has a lower melting point than stearic( Ko, et al., 2010).
REPORT3 Question Four The common characteristic that all amides with antibacterial activity have is nitro and Bromo substituent on the phenyl ring. The nitro and Bromo substituents are the one that causes antimicrobial activity. Their mechanism of action is that amide peptide causes membrane permeation and metabolism disruption as well as interruption of protein and DNA functions of bacteria. Amides are applied in pharmaceutical industries to make antibacterial and antifungal agents against yeast, gram positive and gram negative bacteria (Nugent, 2010). PART B Carbohydrates are a molecular compound that is made up of carbon, hydrogen, and oxygen elements. Carbohydrates are classified into three groups according to their structural features. They include monosaccharides, disaccharides, and polysaccharides. Monosaccharides are the simplest sugars and are made up of one polyhydroxy aldehyde or ketonic unit. Their number of carbon mostly ranges from three to seven and are classified into their functional groups. An aldose sugar is monosaccharides that has aldehyde group whereas a ketose sugar is the one that has ketonic unit. Also, mono sugarscan be classified depending on the number of carbons in the sugar. For examples sugars with three carbons can be referred to as trioses, with five carbon pentoses or with six carbon hexoses. Some examples of monosaccharides include glucose, glyceraldehyde, ribose and dihydroxyacetone (Devlin, 2011). Disaccharides involve more than one monosaccharide unit. The mono sugars are linked together by glycosidic linkages. Some of the common disaccharides include fructose, maltose, and lactose. On hydrolysis, disaccharides sugars yield monosaccharides units which may be similar or dissimilar. On the other hand, polysaccharides consist of a large number of monosaccharides units which may be branched or unbranched. When polysaccharides are hydrolyzed they mostly yield similar monosaccharide units. Some examples of polysaccharides include chitin, gum, mucilage, and pectic substances. Cell membrane serves as a cell wall and cytoskeleton in some organelles. It is composed of a mixture of different classes of molecules. The most common components are lipids and protein.
REPORT4 Lipids are a class of molecules that hat shows a wide diversity in terms of biological function and structure. The main role of lipids is in the formation of permeability of barrier cells in form of a lipid bilayer. The percentage of lipids in the cell membrane can be 20 to 80 percent depending on the location and the function of the membrane in the body. The main component in membrane is phospolipid which forms a lipid bilayer in the cell membrane. This lipid bilayer has two units namely; hydrophilic and hydrophobic units. The hydrophobic side repels water and points away from intracellular fluids whereas hydrophilic unit is attractive to water thus it face intracellular fluids. The hydrophobic tail is able to repel water and faces away from the intracellular and extracellular fluid. The phospholipids organize themselves such that they expose the hydrophilic regions to water and hydrophobic regions away from water (Yeagle, 2011). The arrangement is spontaneous and does not need any energy. This arrangement of phospholipid forms a layer that represents a wall between the inner and outer side of the cell thus playing a crucial role in maintaining the structure of cell membrane. The lipid bilayer is also semi-permeable which makes it allow specific substances to diffuse across the cell membrane. The other important lipid component in the cell membrane is cholesterol. It plays a critical role in making the cell membrane to be rigid thus maintaining the structure of cell membrane. The third lipid component of the cell membrane which helps in maintaining the structure of the cell is glycolipid. Glycolipid consists of the sugar chain and helps the cell to be able to recognize other cells of the body. A protein structure is organized into four different levels namely; primary, secondary, tertiary and quaternary structures. The primary structure provides the description of the specific order arrangements of amino acids which are bonded together to make a chain of the protein referred to as a polypeptide chain (Alipanahi et al., 2015). The primary structure of this polypeptide chain is identified starting at the amino acid which is located at the N-terminus of the polypeptide chain. In regard to this, each amino acid is identified using its abbreviation. A good example of a protein with primary structure is insulin hormone. Insulin is a relatively small protein which consists of fifty-one amino acids. It is composed of two polypeptide chains where polypeptide A consists of twenty-one amino acids and polypeptide B chain thirty amino acids (Li, et al., 2015).
Paraphrase This Document
Need a fresh take? Get an instant paraphrase of this document with our AI Paraphraser
REPORT5 The second level of protein structure is a secondary structure. It is made up by the spatial rearrangement of amino acid that is adjacent to the primary structure Secondary structure is a common occurring structure in most proteins and is formed via hydrogen linkages. Some examples of secondary structure proteins include Beta pleated sheet and an alpha helix. Long chains of the polypeptide will have some parts that either in form of a twist or pleated sheet or alpha helices shape to form secondary structures. The further folding and twists of secondary structure of proteins forms what is called tertiary structure. It is a compact structure which has hydrophilic groups on the surface of the protein molecule and hydrophobic heads which are in the interior. It is the tertiary structure that determines the functional activity of the protein. Examples of tertiary proteins include fibrous and globular proteins. On the other hand, quaternary structure is composed of more than one polypeptide chain which is in a specific orientation with respect to each other. Examples of proteins with tertiary structures include myoglobin and heme (Barrett, 2012). PART C Question One Cyanide affects cellular respiration by inhibiting the key enzyme involved in cellular respiration. It reversibly binds to iron iii ions in the hem group found in the cytochrome oxidase within the mitochondria. This inhibits the electron transport chain blocking the reduction of oxygen to water and ATP (Ochiai, 2012). Question Two DNA Sequence3’- TACGAATCAGCTGTA-5’ Complementary DNA Sequence5’- ATGCTTAGTCGACAT-3’ MRNA seq5- AUGCUUAGUCGACAU
REPORT6 Codon seq=AUG –CUU-AGU-CGA-CAU Amino acid seq= Met-Leu-Ser-Arg-His Question Three The normal Haemoglobin DNA consists of a DNA template made up of CAC-GTG-GAC-TGA- GGA-CTC-CTC-TTC. This DNA template undergoes transcription to form a mRNA complementary to the DNA template mRNA Chain; GUG-CAC-CUG-ACU-CCU-GAG-GAG- AAG By using the messenger RNA chain of normal hemoglobin, the amino acid will be Val-His-Leu- Thr-Pro-Glu Sickle cell hemoglobin DNA template is; CAC-GTA-GAC-TGA-GGA-CAC Then the massager RNA Sickle cell hemoglobin m-RNA = GUG-CAU-CUG-ACU-CCU-GUG The amino acid sequence of sickle cell hemoglobin will be Val-His-Leu-Thr-Pro-Val The difference between normal hemoglobin and sickle cell hemoglobin occurs only in a single amino acid at codon six whereby codon six of normal hemoglobin is Glu and Val in sickle cell hemoglobin. Sickle cell hemoglobin and normal hemoglobin vary from each other in just one amino acid. This distinction in one amino acid causes a lot of differences in the properties of these two kinds of hemoglobin. This difference will also affect the role of hemoglobin an oxygen-carrying protein Question Four a) Adenine- Found in both RNA and DNA
REPORT7 b) Guanine-Found in both RNA and in DNA c) 2-deoxy-D-ribose- Found in DNA d) Cytosine-Found in both RNA and in DNA e) Thymine-Found in DNA f) D-ribose-Found in RNA g) Uracil-Found in RNA only Question Five Depending on the similarity of the sequence, the organism can be ranked as Human, Rhesus monkey, Bullfrog, Tuna, chicken and the furthest organism from the human is silkworm. I think this ranking does not give definite information on how further apart the organism is in evolution. This is because it does not involve crucial information such as features of these organisms. Question Six a)The template strand is in the bottom one with the direction 3’ to 5’. This is supported by the fact that messenger RNA is transcribed in 5’ to 3’ direction. On the other hand, the coding strand is the first which has the direction of 5’-3’ (Meister, 2012). b)The sequence of messanger RNA is AUGGACGGUUGA c)AUG= Met GAC= Asp GGU= Gly UGA= Thr d) Translation of the mRNA: UAC CUG CCA ACU
Secure Best Marks with AI Grader
Need help grading? Try our AI Grader for instant feedback on your assignments.
REPORT8 UAC= Tyr CUG= Asp CCA= Pro ACU= Thr Conclusion In conclusion, the assessment has played a lot in understanding crucial concepts in biochemistry which are related to health science. I can now exhibit my knowledge by applying the principles and concepts in biochemistry which ranges from structure and function of biomolecules to genetic expression, DNA organization, and replication, RNA synthesis, processing, and metabolism. .
REPORT9 References Alipanahi, B., Delong, A., Weirauch, M. T., & Frey, B. J. (2015). Predicting the sequence specificities of DNA-and RNA-binding proteins by deep learning.Nature biotechnology,33(8), 831. Barrett, G. (Ed.). (2012).Chemistry and biochemistry of the amino acids. Springer Science & Business Media. Devlin, T. M. (2011).Textbook of biochemistry. John Wiley & Sons,. Ko, S. H., Su, M., Zhang, C., Ribbe, A. E., Jiang, W., & Mao, C. (2010). Synergistic self- assembly of RNA and DNA molecules.Nature chemistry,2(12), 1050. Li, M., Wang, I. X., Li, Y., Bruzel, A., Richards, A. L., Toung, J. M., & Cheung, V. G. (2011). Widespread RNA and DNA sequence differences in the human transcriptome.science, 1207018. Meister, A. (2012).Biochemistry of the amino acids. Elsevier. Nelson, D. L., Cox, M. M., & Lehninger, A. L. (2005). Principles of biochemistry.WH Freeman and Company, New York, fourth edition edition,1(1.1), 2. Nugent, T. C. (Ed.). (2010).Chiral amine synthesis: methods, developments and applications. John Wiley & Sons. Ochiai, E. I. (2012).General principles of biochemistry of the elements(Vol. 7). Springer Science & Business Media. Rees, D. C., Williams, T. N., & Gladwin, M. T. (2010). Sickle-cell disease.The Lancet,376(9757), 2018-2031. Saenger, W. (2013).Principles of nucleic acid structure. Springer Science & Business Media. Yeagle, P. L. (2011).The structure of biological membranes. CRC press.