TCP/IP Model, Software Development Process and ITSM

Running head: TCP/IP MODEL, SOFTWARE DEVELOPMENT PROCESS AND ITSM
TCP/IP MODEL, SOFTWARE DEVELOPMENT PROCESS AND ITSM
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TCP/IP MODEL, SOFTWARE DEVELOPMENT PROCESS AND ITSM1
1. A station running TCP/IP needs to transfer a file to a host. The file contains 1024
bytes. How many bytes, including all of the TCP/IP overhead, would be sent, assuming
a payload size of 128 bytes and both systems are running IPv4? (Also assume that the
three-way handshake and window size negotiation have been completed and that no
errors occur during transmission.)
Given data:
File size = 1024 bytes
Payload size = 128 bytes.
TCP header = 20 bytes
IPv4 header = 20 bytes.
So total TCP/IP header = 40 (20 + 20) bytes.
1024 bytes is divided into 8 segments, which means each segment has 128 bytes.
Then,
(40+128)*8= 1344 bytes
So total 1344 bytes will be sent and this include TCP/IP overhead.
i) What is the protocol overhead (stated as a percentage)? [3 marks]
IPv4 percentage overhead:
Total overhead that is included in eight segments: 8*40= 320 bytes

TCP/IP MODEL, SOFTWARE DEVELOPMENT PROCESS AND ITSM2
Total data sent: 1024 bytes
Percentage overhead: (320/1024)*100= 31.25%
ii) perform the same calculation, this time assuming that both clients are using IPv6. [2
marks]
File size = 1024 bytes
Payload size = 128 bytes.
TCP header = 30 bytes
IPv6 header = 30 bytes.
So total TCP/IP header = 60 (30 + 30) bytes.
Divide 1024 bytes is divided into 8 segments and this specifies that each segment has 128
bytes.
Then,
(60+128)*8= 1504 bytes
So total 1504 bytes will be sent that includes the overall TCP/IP overhead as well.
Protocol overhead:
IPv6 percentage overhead:
Total overhead in eight segments: 8*60= 480 bytes
Total data sent: 1024 bytes