The two samples hypothesis test is conducted in six steps as

The two samples hypothesis test is conducted in six steps as shown below.
Step 1: Null and alternative hypotheses
Null hypothesis H0 : μHotel=μB∧B
Alternative hypothesis H0 : μHotel ≠ μB∧B
Step 2: Value of test statistic
The independent two sample t test for unequal variance would be used and the t statistic is
computed as highlighted below.
t stat= x 1−x 2
√ s1
2
n1
+ s2
2
n2
t stat= 7.5391−7.7150
√ ( 1.3212 ) 2
32 + ( 1.5794 ) 2
16
=−0.3835
Step 3: The significance level
Assuming a significance level of 5%.
Step 4: Degree of freedom and the p value
Degree of freedom df =
( s1
2
n1
+ s2
2
n2 )
2
( s1
2
n1 )
2
n1−1 +
( s2
2
n2 )
2
n2 −1
df =
( ( 1.3212 ) 2
32 + ( 1.5794 ) 2
16 )
2
( ( 1.3212 ) 2
32 )
2
32−1 + ( ( 1.5794 ) 2
16 )
2
16−1
=25.804 26

The p value for 26 degree of freedom, -0.3835 t test and two tailed test comes out to be
0.7044.
Step 5: Result
Null hypothesis would be rejected when the p value is lower than the significance level. It
can be seen from the above analysis that p value is 0.7044 which is higher than level of
significance and hence, insufficient evidence is present to reject the null hypothesis. Hence,
alternative hypothesis would not be accepted.
Step 6: Conclusion