logo

Transmission and Reflection Operators PDF

18 Pages2848 Words102 Views
   

Added on  2021-05-31

Transmission and Reflection Operators PDF

   Added on 2021-05-31

ShareRelated Documents
Name of the Student Name of the Professor City/State Day/Month/Year Task 2
Transmission and Reflection Operators PDF_1
a)Total capacitance is given by the equation given below 1/CT = 1/C1+1/C21/CT = 1/0.02+1/0.48CT= 0.0192 μFTotal inductance LT= L1+L2LT = 2.1+0.75LT= 2.85 mH Xc= 1/ 2πFc Xc= 1/ (2*3.142*50*2.85*10-6)Xc=1.657MΩXL= 2πFcXL= 2*3.142*50*2.85*10-30.89547Ωb)Voltage and current in the cableZc1= √2.1∗19−30.02∗10−6=√105,000=324.037ῼZc2=√0.75∗10−30.48∗10−6=√15625=39.528ῼ Voltage in cable F" = 2Zc2EZc1+Zc2=2∗39.58820,000324.037+39.528=1,583,200363.565=4354.65V Current in the cable
Transmission and Reflection Operators PDF_2
1= 4354.6539.528=110.166Ac)Transmission and reflection operatorsFrom line A to cableTransmission operator T = 2Zc2(Zc1+Zc2)= 2∗39.528(324.037+39.528)From line A to cable = 79.056363.565= 0.21745From cable to lines A and BReflection operator = T =(Zc2−Zc2)(Zc1+Zc2)= (324.037−39.528)(324.037+39.528)=284.509363.569=0.782553From line A to cableReflection operatorT=(Zc2−Zc1)(Zc1+Zc2)=(39.528−324.037)(324.037+39.528)=−284.509363.569=-0.782553d)Transmission and reflection operators for the cable going into the lineTransmission=2Zc1¿¿
Transmission and Reflection Operators PDF_3
2x324.037324.037+39.528648.079363.565 = 1.78255Reflection = Zc1−Zc2Zc1+Zc2¿¿−284.509363.565¿¿ = -0.78255e) Surge velocityV=1√LC=1√2.1∗10−2∗0.48∗10−6=1√0.000031749=31,497.03km/secf)
Transmission and Reflection Operators PDF_4

End of preview

Want to access all the pages? Upload your documents or become a member.

Related Documents
Understanding Switch Mode Power Supplies (SMPS) and their Role in Efficient Electronics
|31
|4511
|101