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Trigonometry and Geometry - Solved Assignments and Essays | Desklib

   

Added on  2023-06-10

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TABLE OF CONTENTS
Table of Contents.............................................................................................................................1
ASSESSMENT TASK 4.................................................................................................................2
Question 1........................................................................................................................................2
A..................................................................................................................................................2
B...................................................................................................................................................2
Question 2........................................................................................................................................3
Question 3........................................................................................................................................4
A. Perimeter of patch...................................................................................................................4
B. Perimeter of patch...................................................................................................................4
C. Cost of edging.........................................................................................................................5
D. Volume of soil........................................................................................................................5
E. Surface area.............................................................................................................................5
F. Composite soil required...........................................................................................................5
Question 4........................................................................................................................................6
Question 5........................................................................................................................................8
Question 6........................................................................................................................................8
(i) Missing side............................................................................................................................9
(ii) Missing angle.........................................................................................................................9
(iii) Checking answer.................................................................................................................10
Question 7......................................................................................................................................10
1

ASSESSMENT TASK 4
Question 1
A
x = 3 meter and y = 5 meter as opposite sides of rectangle are equal
X= 5 cm
y can be calculated using pythagorus theorem
y2 = 52 – 2.52
y2 = 25 – 6.25
y = 4.33 cm
B.
Radius of circle is half of the diameter. Given that diameter is 2.75 cm, radius is equals to 1.375
2

Question 2
Shape
Write the name of the
shape
Perimeter
Write correct units
Area
Write correct units
a
Rectangle
Formula: 2 [l +b] where l is length
and b is breadth of rectangle
Perimeter = 2 * [3+5]
Perimeter = 16 meter
Formula: l*b
Area = 3 *5
Area = 15 meter 2
b Triangle Formula: a+b+c
where a,b and c are sides of the
triangle
Answer: Perimeter = 5+5+5 = 15 cm
Formula: 0.5 * base * height
Answer: 0.5 * 5* 4.33
area = 10.82 cm 2
c
circle
Formula: 2* π *r
where r is the radius of circle
Answer:
Given diameter = 2.75 cm
radius r = 1.375 cm
Perimeter = 2 * 3.14 * 1.375
Perimeter = 8.63 cm
Formula: π *r * r
Answer:
Area = 3.14 * 1.375 * 1.375
area = 5.93 cm2
3

Question 3
A. Perimeter of patch
The vegetable patch will be in shape of rectangle with length 6 meter and width 2 meter.
Perimeter of rectangle = 2 [Length + width]
= 2 * [2+6]
Perimeter = 16 meter
B. Perimeter of patch
New length of rectangular part = 4 meter
Diameter of semicircle = 2 meter
Radius of semicircle = 1 meter
The two semicircles each of diameter 2 meter makes one circle. Thus circumference of circle is
= 2 * 3.14 * r
4

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