Unit Assessment Part-2 | Assignment

Running head: UNIT 1 ASSESSMENT, PART 2
UNIT 1 ASSESSMENT, PART 2
Name of the Student
Name of the University
Author Note

UNIT 1 ASSESSMENT, PART 21
1.
Given f(x) = -x^2 + 7x – 6
zeroes => -x^2 + 7x – 6 = 0
 x^2 - 7x + 6 = 0
 x^2 – 6x – x + 6 = 0
 (x-1)(x-6) = 0
 x = 1 and 6
maxima and minima => f’(x) = 0
 -2x + 7= 0
 x = 3.5
at x = 3.5 f’’(3.5) = -2 <0 (hence, x = 3.5 is maximum)
at f(3.5) = 6.25
x domain = (-∞,∞)
y range = (-∞,6.25]
The function is a parabola with shifted y axis at x = 3.5.
Reciprocal of f(x) = g(x) = 1/(-x^2 + 7x – 6)
Domain => -x^2 + 7x – 6 ≠0
 x ≠ 1 or 6.
Vertical asymptotes x = 1 x = 6.

UNIT 1 ASSESSMENT, PART 22
Graph of both functions:
2.
a.
f(x) = −2 x – 5
3 x +18
Vertical
asymptotes
Horizontal
asymptotes
x-intercept y-intercept Domain
x = -6 y = -2/3 (-5/2,0) (0,-5/18) (-∞,-6)U(-
6,∞)
Graph of function: