Using Numeracy Data & IT - Desklib

Using Numeracy Data & IT

TABLE OF CONTENTS
PART 1............................................................................................................................................3
Question 1...................................................................................................................................3
Question 2...................................................................................................................................3
Question 3...................................................................................................................................3
Question 4...................................................................................................................................3
Question 5...................................................................................................................................4
Question 6...................................................................................................................................4
Question 7...................................................................................................................................4
Question 8...................................................................................................................................5
Question 9...................................................................................................................................5
Question 10.................................................................................................................................5
PART 2............................................................................................................................................6
Question 11.................................................................................................................................6
PART 3............................................................................................................................................7
Question 12.................................................................................................................................7
Question 13.................................................................................................................................8
Question 14...............................................................................................................................10
Question 15...............................................................................................................................12
Question 16...............................................................................................................................13
REFERENCES..............................................................................................................................15

PART 1
Question 1
Numerator- it is being defined as the part of fraction which represent the fact that how many
parts are being considered out of the whole fraction (Sawe, Chafe and Treviño, 2020). This is the
number which comes above the line in a fraction.
Denominator- the denominator is the number which represents the total number of equal parts in
the whole. It is the number which comes below the line within the fraction.
For instance, 4 / 5 is a fraction, then in this case 4 is numerator and 5 is denominator.
Question 2
24/ 40 = 3/5
18/ 42= 3/7
Question 3
a
2/3 * 4/4 = 8/12
3/4 * 3/3 = 9/12
5/6 * 2/2 = 10/12
b
The book remaining = 60000 – (14000 + 22000 + 12000)
= 60000 – 48000
= 12000 books
The computing book counts for 2 / 3 of remaining books
= 12000 * 2 / 3 = 8000
So the total of computing book is 8000 books.
Also, the total percentage of computing book
= 8000 / 60000 * 100
= 13.33 %
This implies that computing books counts for 13.33 % of the total book.
Question 4
Number of shoes purchased = 2
Note provided = 50

Total number of notes = 3
So total money provided = 50 * 3 = 150
Money returned by shopkeeper is 10.50
For calculation of price of both shoes = money paid – money received
= 150 – 10.50 = 139.50
Thus, the total money paid for pair of two shoes is 139.50
So price of one pair of shoe = 139.50 / 2
= 69.75
Question 5
A
240.50 * 19.54 = 6499.37
B
5.21* 10^4
Question 6
A
Total money paid by three siblings = 210
Total discount received = 30 %
Thus, this implies that 70 % payment is made which is 210.
So for 1 % = 210 / 70 = 3
For 100 % payment is 300
Thus, the total saving made is 300 – 210 = 90
B
Total saving done by each person = total saving / total number of people
= 90 / 3 = 30 per sibling
Question 7
A
Firstly, convert the fraction in simplest form which involves-
3/4 = 0.75
7/9 = 0.78
2/3 = 0.66