Numeracy, Data & IT Study Material

Using Numeracy, Data & IT

Table of Contents
INTRODUCTION...........................................................................................................................3

TASK 1
Q1.
Numerator: This really is the amount put at the top of a proportion. This illustrates how often
pieces it has.
Denominator: The lower portion of the proportion is added. It indicates however many two
portions the output is broken into.
Q2.
24/40 = 0.6
18/42 = 0.43
Q3.
a) 2/3, 3/4 and 5/6
8
12 ,
9
12 ∧10
12
b) Proportion of books in library on calculation
Remainder book = 60,000 – 14,000 – 22,000 – 12,000
= 12,000
Computer books = 12,000 × 2
3
= 8,000
% of books on computing = 8,000
60,000 ×100
= 13.33%
Q4.
Actual money provided by Liz = £50 × 3 = £150
Overall price of two shoes pairs = £150 - £10.50
= £139.50
Price per pair of shoes = £139.50/2
= £69.75 per pair
Q5.
a) 240.50 × 19.54

= 4,699.37
b) 521 × 1010
Q6.
a)
Actual amount given for signing up = £210
Overall discount obtained= £210 × 30
100
= £63
Thus, the overall savings = £63
b)
Aggregate savings of specific person = £63 / 3 (Patty including 2 siblings)
= £21 per person
Q7.
a) 3/4 - 7/9 + 2/3
Applying BODMAS = 17/12 – 7/9
= 237/108
b) 0.1
Q8.
Total No. of people agree with the fact = (90 + 60) × 3
5
= 90
Actual number of female agree= 60 × 3
10
= 18
Overall men’s said yes = 90 – 18
= 72
No. of man Disagree = 90 -72 = 18
% of the men said no = 18
90 × 100
= 20%
Q9.
The reversed calculation method will be employed here: