Wireless Networks & Communications: Encoding, Error Control, Multiplexing, and Wi-Fi

WIRELESS NETWORKS & COMMUNICATIONS
[Author Name(s), First M. Last, Omit Titles and Degrees]
[Institutional Affiliation(s)]

Part I: Encoding and error control
a) Calculate the data rate required for robot to remote controller communication
Data rate is the number of bits sent per second=16/2=8 mbps
b) Explain 3 types of suitable encoding techniques could be used to encode the status string.
i. Differential Manchester: A binary zero is illustrative of the presence of a
transition at the start of a bit
ii. Manchester encoding: A transition occurs at the middle of each of the bits that
have been transmitted. A binary zero hints a low to high transition that occurs in
the middle while a low to high transition is hinted by a binary one (Lu et al.,
2015).
iii. Pseudo-ternary encoding: In this encoding, the absence of a line illustrated a one
while a zero is indicated using an alternating positive and negative. A long string
of zeros do not lead to any loss in the synchronization
c) i. Write the status string in binary for this instance
Step 1: the initial step is to change the provided parameters to binary notation

Motor functionality = 1111
5m/s = 0101
75%= 0.11
48cm = 110000
Step 2: Combination of all the binary to come up with a single string
0101110000111111
ii. Represent the status string on ASK, FSK, and PSK encoding techniques
FSK: Switching or alteration occurs to the carrier wave frequency upon the transmission of logic
but no variations occur to the carrier on transmission of logic zero.
ASK: In the occurrence of a transmission, logic one undergoes transmission over the media. A
logic zero returns no carrier signal transmission over a network.
PSK: A change from a logic one to zero or zero to one changes the phase angle by 180⁰ while no
lack of a transition in the data bots does not result into a change in the phase.

d) Calculate the CRC for the status string derived in c) with polynomial divisor 11001101
Dividend is given as 0101110000111111
Divisor is provided as = 11001101
Stage 1: Sum up the digits of the dividends
= No. of divisors -1= 8-1= 7 units.
Stage 2: Sum up additional digits to the data word to come up with argument data word
= 01011100001111110000000