A function is declared: void bazz(long A[], long ...
11 Oct 2021
A function is declared: void bazz(long A[], long B[], int n) { /* …. */ } The compiler, given -Og option, generates the following code: movl $0, %eax .L2: cmpl %edx, %eax jge .L4 movslq %eax, %rcx movq (%rsi, %rcx, 8), %r8 addq %r8, (%rdi, %rcx, 8) addl $1, %eax jmp .L2 .L4: ret (Note: the movslq instruction moves and sign-extends the low-order 32 bits of a register to the full 64-bit destination register.) Write the C code for the body of this function.
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Solutions
11 Oct 2021
from the given problem, let's break down the code generated by the compiler: step 1: movl $0, %eax it means that, int * eax = (int *)0...
Solutions
22 Oct 2021
ddd...
Solutions
27 Oct 2021
x registers. rsi, register holds array A, and rcx register holds array B value. Assume array address is stored in rsi register and index is stored ...
Solutions
29 Oct 2021
ggd...
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