The value of pi can be approximated ...
06 Sep 2021
The value of pi can be approximated using the following series: pi = 4(1 - 1/3 + 1/5 - 1/7 + ... + 1/(2n-1) + 1/(2n+1)) The following program uses this series to find the approximate value of pi. However, the statements are in the incorrect order, and there is also a bug in this program. Rearrange the statements and remove the bug so that this program can be used to approximate pi. As with the other file, use inline comments to document your changes. Once the program is running, run it several times, and put a copy of the output into a block comment (like this one) at the bottom of the code. #include <iostream> #include<iomanip> using namespace std; int main() { double pi = 0; long i; long n; cin >> n; cout << "Enter the value of n: "; cout << endl; if (i % 2 == 0) pi = pi + (1 / (2 * i + 1)); else pi = pi - (1 / (2 * i + 1)); for (i = 0; i < n; i++) { pi = 0; pi = 4 * pi; } cout << endl << "pi = " << pi << endl; return 0; }
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Solutions
06 Sep 2021
The Correct sequence of the C++ Code of the above problem to implement pi value is: The output of the above code is shown below: ...
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