HNCB Principles of Structural Design: Bending Moments & Shear Forces

This assignment solution covers key aspects of structural design, focusing on bending moments and shear forces in beams. It includes detailed calculations for various load scenarios on simply supported beams, determining shear forces, bending moments, and deflections. The solution also explores statutory requirements, dead and live loads, and codes of practice relevant to structural design. Furthermore, it examines the impact of deflection on structural stability, different methods of support for structures, and the concept of slenderness ratio. The assignment also includes the determination of axial load carrying capacity for steel and reinforced concrete columns, along with a comparison of material costs and the application of basalt rebar reinforcement.

BENDING MOMENTS & SHEAR FORCES WITH BEAM
DESIGN CONSIDERATIONS
HNCB 20- PRINCIPLES OF STRUCTURAL DESIGN
1

Table of Contents
Task 1...............................................................................................................................................4
Task 2.............................................................................................................................................16
Task 3.............................................................................................................................................20
Task 4.............................................................................................................................................22
Reference list.................................................................................................................................26
2

Task 1
1 (A)
A
Given data
L = 14m [Length of beam]
P = 150KN [Point load on Beam]
Taking moment from A
(150*7) + (-RB*14) = 0
1050 – 14 RB = 0
14 RB = 1050
RB = 1050/14
3

RB = 75 ------------- [1]
Summation of upward force and downward force
RA – 150 +RB = 0
RA = 150 – 75
RA = 75 KN -------- [2]
Calculation of Shear force
FA = 75 KN
FB = 75-150 = -75 KN
FC = -75 KN
Calculation of bending moment
MA = 0
MB = 75*7 = 525 KN.m
MC = 0
4

B
5

Taking moment from A
- (65*2) +RB*8 = 0
8RB = 65*2
RB =16.25
Summation of all forces
RA – 65 + 16.25 = 0
RA = 48.75KN
Shear force
FA = 48.75
FC = -16.25
FB= -16.25
Bending moment
MA = 0
MC = 48.75*2 = 97.5 KN
6

MB =0
C
Taking moment from A
625*12.5 – RB*25 = 0
RB = 625 *12.5/25
RB = 312.5 KN
Summation of all forces
7

RA – 625 +312.5= 0
RA = 312.5 KN
Shear force
FA = 312.5
FC = 312.5-(25*12.5) = 0
FB = -312.5
Bending moment
MA = 0
MC = 1953.125
MB =0
D
8

Taking moment from A
14*RB = 150*7 + 280*7
RB = 1050+1960
RB = 3010 / 14
RB = 215 KN
Summation of all forces
RA – 150-280-215
RA =430-215
RA = 215
Shear force
FA = 215 KN
FC = 215-150-(20*7) = 214-290 = -76 KN
FB = -76-(20*7) = -216 KN
9

Bending moment
MA = 0
MC = 215*7 – 20*7*3.5 = -1015 KN
MB =0
E)
Taking moment from A
- (625*12.5) – (20*15) = RB*25
RB = 85625/25
RB = 342.5 KN
10

Summation of all forces
RA - 625- 50+ 342.5 = 0
RA = 332.5 KN
Shear force
FA = 332.5KN
FC = 332.5-625 = -292.5 KN
FD = -292.5 – 50 = -342.5 KN
FB = -342.5 - 250 = 592.5 KN
Bending moment
MA = 0
MC = (332.5*12.5) = 4156.25 KN
MD = (342.5*10) = 3425 KN
MB =0
11

Task 1 (B)
Statutory requirements are needed consider vigilantly during structural design so that potential
risks and issues can be minimized as far as possible. The first requirement is planning permission
that implies that legitimate steps have been undertaken especially in construction management.
On the contrary, shear stress and bend moment are essential components of structural design
within construction sites that reduce the risk of failure as far as possible
(Connect.bim360.autodesk.com, 2019). In construction, the permission from ministry, local
government and building regulatory are important to make sure risk of failure can be minimized
eventually.
Task 1 (C)
Dead Loads for common Residential construction
Construction option Load
Roof construction 15psf
Floor construction 10psf2
Wall construction 6Psf
Foundation construction 75psf
Table 1: Dead Loads for common Residential construction
Live loads for residential construction
Application Uniform load Concentrated load
Roof 15 psf 250 lbs
Attic 10 psf 250 lbs
Floors 20 psf 250 lbs
Decks 40 psf 300 lbs
Balconies 60 psf 300 lbs
Stairs 40 psf 300 lbs
Guards and handrails 20 psf 300 lbs
Table 2: Live loads for residential construction
Minimum imposed loads
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