Numeracy, Data and IT Assessment: A Practical Guide
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Using Numeracy, Data and IT
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Contents
List Of figures..................................................................................................................................3
Section 1..........................................................................................................................................5
Question 1....................................................................................................................................5
Question 2....................................................................................................................................6
Question 3:...................................................................................................................................7
Question 4....................................................................................................................................9
Question 5..................................................................................................................................10
Question 6..................................................................................................................................11
Question 7..................................................................................................................................12
Question 8..................................................................................................................................13
Question 9..................................................................................................................................14
Question 10................................................................................................................................15
Section 2........................................................................................................................................16
11 Solution:....................................................................................................................................16
11 a):..........................................................................................................................................16
11 b):..........................................................................................................................................18
11 c):..........................................................................................................................................18
11 d):..........................................................................................................................................19
11 e):..........................................................................................................................................20
11 f):...........................................................................................................................................21
12 Solution.....................................................................................................................................22
12 a.............................................................................................................................................22
12 b............................................................................................................................................22
12 c.............................................................................................................................................23
12 d............................................................................................................................................24
12 e.............................................................................................................................................25
Assessment 2.................................................................................................................................26
a)................................................................................................................................................26
b. Solution:.................................................................................................................................29
c) Solution:.................................................................................................................................33
List Of figures..................................................................................................................................3
Section 1..........................................................................................................................................5
Question 1....................................................................................................................................5
Question 2....................................................................................................................................6
Question 3:...................................................................................................................................7
Question 4....................................................................................................................................9
Question 5..................................................................................................................................10
Question 6..................................................................................................................................11
Question 7..................................................................................................................................12
Question 8..................................................................................................................................13
Question 9..................................................................................................................................14
Question 10................................................................................................................................15
Section 2........................................................................................................................................16
11 Solution:....................................................................................................................................16
11 a):..........................................................................................................................................16
11 b):..........................................................................................................................................18
11 c):..........................................................................................................................................18
11 d):..........................................................................................................................................19
11 e):..........................................................................................................................................20
11 f):...........................................................................................................................................21
12 Solution.....................................................................................................................................22
12 a.............................................................................................................................................22
12 b............................................................................................................................................22
12 c.............................................................................................................................................23
12 d............................................................................................................................................24
12 e.............................................................................................................................................25
Assessment 2.................................................................................................................................26
a)................................................................................................................................................26
b. Solution:.................................................................................................................................29
c) Solution:.................................................................................................................................33

d)................................................................................................................................................36
References......................................................................................................................................38
List Of figures
Figure 1 : Tally marks table.............................................................................................................5
Figure 2: Data Tab available on Spreadsheet................................................................................17
Figure 3: Option for Shorting available on the spreadsheet..........................................................17
Figure 4: Shorted data in ascending order (alphabetical)..............................................................17
Figure 5: List of employee worked "<35" hours a week...............................................................18
Figure 6: Count of employee earned more than the average amount............................................19
Figure 7: Net Amount earned graph..............................................................................................20
Figure 8: Columns with replication of data...................................................................................20
Figure 9: Calculation of result value in cell H20...........................................................................21
Figure 10: Calculation of total no. of females...............................................................................22
Figure 11: Calculation of records (<£25 hourly rate)....................................................................23
Figure 12: Calculation of surnames starting with “P”...................................................................24
Figure 13: Calculation of the total sum of the amount earned by females which are “>=£495”. .25
Figure 14: Finding “Messi” and his deduction..............................................................................25
Figure 15 : Table showing the total spending................................................................................26
Figure 16 : Table showing the mean..............................................................................................27
Figure 17 : Table showing the median..........................................................................................28
Figure 18 : Table showing the standard deviation.........................................................................29
Figure 19: Line graph established for the spending done over “Food” by students......................30
Figure 20: Line graph established for the spending done over “Clothing” by students................31
Figure 21: Line graph established for the spending done over “Entertainment” by students.......32
Figure 22: Line graph established for the spending done over “Charitable Giving” by students. 33
Figure 23: Scatter diagram designed for Food..............................................................................34
Figure 24: Scatter diagram designed for Clothing.........................................................................34
Figure 25: Scatter diagram designed for Entertainment................................................................35
Figure 26: Scatter diagram designed for Charity...........................................................................36
References......................................................................................................................................38
List Of figures
Figure 1 : Tally marks table.............................................................................................................5
Figure 2: Data Tab available on Spreadsheet................................................................................17
Figure 3: Option for Shorting available on the spreadsheet..........................................................17
Figure 4: Shorted data in ascending order (alphabetical)..............................................................17
Figure 5: List of employee worked "<35" hours a week...............................................................18
Figure 6: Count of employee earned more than the average amount............................................19
Figure 7: Net Amount earned graph..............................................................................................20
Figure 8: Columns with replication of data...................................................................................20
Figure 9: Calculation of result value in cell H20...........................................................................21
Figure 10: Calculation of total no. of females...............................................................................22
Figure 11: Calculation of records (<£25 hourly rate)....................................................................23
Figure 12: Calculation of surnames starting with “P”...................................................................24
Figure 13: Calculation of the total sum of the amount earned by females which are “>=£495”. .25
Figure 14: Finding “Messi” and his deduction..............................................................................25
Figure 15 : Table showing the total spending................................................................................26
Figure 16 : Table showing the mean..............................................................................................27
Figure 17 : Table showing the median..........................................................................................28
Figure 18 : Table showing the standard deviation.........................................................................29
Figure 19: Line graph established for the spending done over “Food” by students......................30
Figure 20: Line graph established for the spending done over “Clothing” by students................31
Figure 21: Line graph established for the spending done over “Entertainment” by students.......32
Figure 22: Line graph established for the spending done over “Charitable Giving” by students. 33
Figure 23: Scatter diagram designed for Food..............................................................................34
Figure 24: Scatter diagram designed for Clothing.........................................................................34
Figure 25: Scatter diagram designed for Entertainment................................................................35
Figure 26: Scatter diagram designed for Charity...........................................................................36
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Figure 27 : Table showing the spending more than 500................................................................36
Figure 28 : Table showing the persons who are married...............................................................37
Figure 29 : Table showing the persons based in London..............................................................37
Figure 30 : Table showing final probability..................................................................................37
Figure 28 : Table showing the persons who are married...............................................................37
Figure 29 : Table showing the persons based in London..............................................................37
Figure 30 : Table showing final probability..................................................................................37
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Section 1
Question 1: What is the result of the following calculation? Leave your answer in a tally
format.
I I I I I I I – I I I I
Solution - The above digits are written in the Roman form which is also known as tally marks,
thus firstly we have to convert this in the numerical form.
Figure 1 : Tally marks table
The numerical form of these digits are written as -
I I I I = 5, I I I = 3, I I I I = 4
= 5 + 3 - 4
= 8 - 4
= 4
The output which has been attained in numerical Form is 4
Thus, the tally marks output will be display in the form = I I I I
Question 1: What is the result of the following calculation? Leave your answer in a tally
format.
I I I I I I I – I I I I
Solution - The above digits are written in the Roman form which is also known as tally marks,
thus firstly we have to convert this in the numerical form.
Figure 1 : Tally marks table
The numerical form of these digits are written as -
I I I I = 5, I I I = 3, I I I I = 4
= 5 + 3 - 4
= 8 - 4
= 4
The output which has been attained in numerical Form is 4
Thus, the tally marks output will be display in the form = I I I I

Question 2:
What percentage of 70 does 49 equate to?
Solution - The above statement can be written as 70*100: 49
To attained the result of the above statement, the following steps must be followed -
Step 1 - This is to be assumed that 70 is 100%.
Step 2 - The next is to denote the seek value with x
Step 3 - The step 1 is to be follows that 100% is equal to 70
Step 4 - In the same manner, x% is equals to 49
Step 5 - The pair of simple equations is generated, which is outlined as below -
Equation 1 = 100 % is equals to 70
Equation 2 = X% is equals to 49
Step 6 - In this step equation 1 is going to be divided by equation 2, and the equations of left
hand side are same (%). Thus, now this will displayed as
100%/ x% = 70/49
Step 7 - Now, just reciprocal both of the sides
x%/100% = 49/70
Thus, x will equals to 70%
Therefore, the output which is generated is 70% is 49 of 70.
Thus, the result is 70
What percentage of 70 does 49 equate to?
Solution - The above statement can be written as 70*100: 49
To attained the result of the above statement, the following steps must be followed -
Step 1 - This is to be assumed that 70 is 100%.
Step 2 - The next is to denote the seek value with x
Step 3 - The step 1 is to be follows that 100% is equal to 70
Step 4 - In the same manner, x% is equals to 49
Step 5 - The pair of simple equations is generated, which is outlined as below -
Equation 1 = 100 % is equals to 70
Equation 2 = X% is equals to 49
Step 6 - In this step equation 1 is going to be divided by equation 2, and the equations of left
hand side are same (%). Thus, now this will displayed as
100%/ x% = 70/49
Step 7 - Now, just reciprocal both of the sides
x%/100% = 49/70
Thus, x will equals to 70%
Therefore, the output which is generated is 70% is 49 of 70.
Thus, the result is 70
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Question 3:
a). Complete the table to show equivalent fractions and percentages.
Table 1: Fraction and Percentage table
Solution - To attained the output for the above table, the following steps must be followed by the
learner and these are stated below -
Step 1 - x% is equals to X by 100, thus the substitute for x is 45, so this can be written has
45% = 45/100
Now, divide both the sides by 5 in order to reduce the fraction in the easiest form which is 9/20.
Thus the fraction of 455 is 9/20.
Step 2 - The percentage of 2/3 is…,
The percent of any number in the fraction can be written with the denominator of 100, in this 3 is
not the factor of 100.
Thus, 2/3*100 = 200/3%
The three is a problem as this is ending as the recurring decimals.
1/3 is commonly written as 33.3%. Thus in the same way 2/3 can be written as 66.7%
Therefore, the result is 66.7%
Step 3 - The fraction for 22.5% is
Any of the percentage number can be written with the denominator of 100, thus 22.5 % can be
written in the form of 22.5/100
Fraction Percentage
45%
2/3
22.5%
7/5
a). Complete the table to show equivalent fractions and percentages.
Table 1: Fraction and Percentage table
Solution - To attained the output for the above table, the following steps must be followed by the
learner and these are stated below -
Step 1 - x% is equals to X by 100, thus the substitute for x is 45, so this can be written has
45% = 45/100
Now, divide both the sides by 5 in order to reduce the fraction in the easiest form which is 9/20.
Thus the fraction of 455 is 9/20.
Step 2 - The percentage of 2/3 is…,
The percent of any number in the fraction can be written with the denominator of 100, in this 3 is
not the factor of 100.
Thus, 2/3*100 = 200/3%
The three is a problem as this is ending as the recurring decimals.
1/3 is commonly written as 33.3%. Thus in the same way 2/3 can be written as 66.7%
Therefore, the result is 66.7%
Step 3 - The fraction for 22.5% is
Any of the percentage number can be written with the denominator of 100, thus 22.5 % can be
written in the form of 22.5/100
Fraction Percentage
45%
2/3
22.5%
7/5
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Thus, the result which is attained is 9/40.
Step 4 - The next and last is the percentage of 7/5
Thus, when the percentage is divided by 100, in the similar way the fractions are multiplied by
100.
Thus, the 7/5 can also be written as 1.4, and when this is converted into the percentage form, the
1.4 is multiplied by 100.
The attained result is 14%
Hence, the table is completed and shown below -
Table 2: Solved Fraction and Percentage table
Fraction Percentage
9/20 45%
2/3 66.7%
9/40 22.5%
7/5 14%
b). A carton contains 150 cereal bars. What fraction of this number will each person get
when distributed to a class of 20 students?
Solution - Number of carton = 1
Number of cereal bars = 150
Total number of students = 20
Each student will get the following number of cereal bar = 150/20
The result is 15/2 which is also written as 7 ½.
Step 4 - The next and last is the percentage of 7/5
Thus, when the percentage is divided by 100, in the similar way the fractions are multiplied by
100.
Thus, the 7/5 can also be written as 1.4, and when this is converted into the percentage form, the
1.4 is multiplied by 100.
The attained result is 14%
Hence, the table is completed and shown below -
Table 2: Solved Fraction and Percentage table
Fraction Percentage
9/20 45%
2/3 66.7%
9/40 22.5%
7/5 14%
b). A carton contains 150 cereal bars. What fraction of this number will each person get
when distributed to a class of 20 students?
Solution - Number of carton = 1
Number of cereal bars = 150
Total number of students = 20
Each student will get the following number of cereal bar = 150/20
The result is 15/2 which is also written as 7 ½.

Question 4:
Solution - Total number of discount-priced football tickets purchased by Samuel = 3
Samuel paid for 3 tickets = £50
The amount given back to Samuel was £4.20
The amount paid for 3 tickets = £50 - £4.20
= £45.8
Thus, cost of each ticket is £45.8/3 = £15.26.
Solution - Total number of discount-priced football tickets purchased by Samuel = 3
Samuel paid for 3 tickets = £50
The amount given back to Samuel was £4.20
The amount paid for 3 tickets = £50 - £4.20
= £45.8
Thus, cost of each ticket is £45.8/3 = £15.26.
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Question 5:
a). Solve this binary arithmetic: 10011 +10101.
Solution - To attain the result for the above binary arithmetic, the following digits must be
converted into the decimal form.
Number 1 in the form of decimal will be displayed as:
100112 = 1910
Number 2 in the form of decimal will be shown as:
101012 = 2110
Now, there sum will be 19+21, which is equals to 40
The output which is generated in binary form is 4010, which is equals to 1010002
b). Write the number 0.0101 as a power of 10.
Solution - The value of 0 will remain 0 only and the value for 1 will be based on their location.
Thus, this can be written as 10-2 + 10-4 which is equals to 10-6.
Therefore the result is 10-6
a). Solve this binary arithmetic: 10011 +10101.
Solution - To attain the result for the above binary arithmetic, the following digits must be
converted into the decimal form.
Number 1 in the form of decimal will be displayed as:
100112 = 1910
Number 2 in the form of decimal will be shown as:
101012 = 2110
Now, there sum will be 19+21, which is equals to 40
The output which is generated in binary form is 4010, which is equals to 1010002
b). Write the number 0.0101 as a power of 10.
Solution - The value of 0 will remain 0 only and the value for 1 will be based on their location.
Thus, this can be written as 10-2 + 10-4 which is equals to 10-6.
Therefore the result is 10-6
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Question 6:
a) What were the total savings made?
Solution - Here the new salon has been inaugurated and in that case they are promoting there
business by rendering different offers to their customers.
The offer is of 20% till 2 weeks, so Janice and her friends had an hair cut for the total amount
of £100. Thus this is to calculate the total savings made by Janice and her friends will be -
Let the value will be x
So, the total savings will be x*20% which is equals to 100
Thus, the result is 125
b) Work out the average savings amount if 4 hairdos were done?
Solution - The average savings amount will be 100/4 (25+25+25+25/4)
This is equals to 25
a) What were the total savings made?
Solution - Here the new salon has been inaugurated and in that case they are promoting there
business by rendering different offers to their customers.
The offer is of 20% till 2 weeks, so Janice and her friends had an hair cut for the total amount
of £100. Thus this is to calculate the total savings made by Janice and her friends will be -
Let the value will be x
So, the total savings will be x*20% which is equals to 100
Thus, the result is 125
b) Work out the average savings amount if 4 hairdos were done?
Solution - The average savings amount will be 100/4 (25+25+25+25/4)
This is equals to 25

Question 7:
a). Work out the mean of the seven numbers.
Solution - Mean can be calculated as = sum of all the observations/ No. of observations
= 5+12+12+8+4+10+5 / 7
= 56/ 7
The Mean result is 8
b) What is the mode of the seven numbers?
Solution - The mode is the number which is repeated many times.
The mode result is 12 because this has occurred two times.
a). Work out the mean of the seven numbers.
Solution - Mean can be calculated as = sum of all the observations/ No. of observations
= 5+12+12+8+4+10+5 / 7
= 56/ 7
The Mean result is 8
b) What is the mode of the seven numbers?
Solution - The mode is the number which is repeated many times.
The mode result is 12 because this has occurred two times.
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