Information Signals Analysis and Communication Systems - Solution

This document presents a detailed solution to an electrical engineering assignment focused on information signals and communication systems. The assignment covers a range of topics, including analyzing information signals, calculating signal characteristics like amplitude, frequency, and phase angle, and applying Fourier transforms. The solution also delves into communication systems, discussing concepts such as bandwidth calculation, channel capacity, and circuit switching techniques. Furthermore, the document provides practical examples and calculations related to signal processing, including pixel rates, signal-to-noise ratio (SNR), and the application of the Nyquist rate. The assignment also explores the concepts of circuit switching and virtual circuits. Finally, the solution provides a comprehensive understanding of the theoretical aspects and practical applications of information signals in communication systems.

Information signal 1
INFORMATION SIGNALS
By Name
Course
Instructor
Institution
Location
Date

Information signal 2
Question 1
Ordering a pizza
The below figure illustrates ordering Pizza
Description
1. The guest recommends the pizza menu, then the host gives the menu to the guest, the guest
chooses his or her Pizza and places the order.
2. The guest looks for telephone number, picks up the phone and call it. The phone connects to
telephone line and send tones to the number dialed.
3. Host communicate with order clerk, give the guest pizza order, recognizes order and guest
then wait.
4. Order Clerk gets the order, ask more info about the payment, and accepts info about the
payment, places order to Pizza cook.
Delivering Pizza
The figure below illustrates the pizza delivery;

Information signal 3
The below are the steps ;
1. The pizza cook prepares Pizza according to the guest order and allocates to the clerk
responsible of the order (Sandhu, 2010).
2. This clerk packed the pizza, prepares delivery receipt and put in delivery van.
3. Delivery van transfers all the ordered Pizzas from the clerk and delivered it to host. Here
road acts like a transmitting line between ordering and delivering of pizza system.
4. Host confirms the payment details and returns to the order clerk and approves delivery.
5. Finally, the host passes Pizza to guests (Lucey, 2010).
QUESTION 2
Both the Chinese and French Prime minister must have English translator;

Information signal 4
The processes well described by numbering system;
QUESTION 3

Information signal 5
Therefore the maximum amplitude is 15
Time period (T) = 3 seconds
Frequency = 1/T = 1/ 3 = 0.3333Hz
Sine ( wt+φ ) = 0
Phase angle is 00
Angle = 00
Therefore the phase angle is 00

Information signal 6
Amplitude is 4
Time is 6.5 seconds
Frequency = 1/T = 1/ 6.5 = 0.1538 Hz
Sine ( wt+φ ) = 0
Phase angle is 00
Angle = 00

Information signal 7
Amplitude is 7.5
Period = 2.25
Frequency = 1/T = 1/2.25 = 0.444 Hz
0
Sine ( wt+φ ) = amplitude
Phase angle is 00
Sin φ=1
Therefore phase angle is 900
QUESTION FOUR

Information signal 8
a.
From
A sin ( 2 π ( f ) t
Where ;
A = Amplitude
f= Frequency
t = Time period = 1/f
10 sin ( 2 π (100 ) t
Therefore
Amplitude = 10
Frequency = 100 Hz
Time period = 1/100 = 0.01 second
Phase = 0
And this can be drawn as below;

Information signal 9
b.
20 sin ( 2 π ( 30 ) t
Amplitude= 20
Frequency = 30Hz
Time priod = 1/30 = 0.33 seconds
Phase is 0
And the waveform is illustrated using the following diagram;

Information signal 10
c.
5 sin (500 π (180 ) t
Amplitude = 5
Frequency = 500
2 = 250 Hz
Time period = 1/ 250 = 0.04 seconds
Phase angle is 1800
The shift plot to left by 180 phase shift
And the waveform can be illustrated using the following diagram;
d.
8 sin (400 π ( 270 ) t
Amplitude = 8
Frequency = 400
2 = 200 Hz

Information signal 11
Time period =1/200 = 0.005 seconds
The phase angle is 2700
And the waveform is illustrated using the following diagram
QUESTION FIVE
a.
Pixels/ second = ( 480*500)* 30
Pixel/ second= 7200000
Each pixel can take 32 value
Therefore Log2 (32) = 5
So 5 bits / pixel .
Source rate R = 7200000×5
Source rate R = 36000000 = 36×106 Mbps

Information signal 12
b.
B=4.5 * 106
SNRdbB= 35=10log10 (SNR)
=31632
C = 4.5*106( 1+31632)log 2
C = 4.5*106(log2(31632)
C= 4.5*106* 11.6272
= 52.32*106 bps
QUSTION SIX
4Ghz = 4 x 109 Hz
35863 Km = 35.863 x 106 m
=> (20log10(4x10^9)) + 20log10(35.863x10^6) - 147.56
= 195.574 dB
QUESTION SEVEN
𝑠(𝑡) = 5 sin(200𝜋𝑡) + sin(600𝜋𝑡)
Suppose we have 3 frequencies as signal f1,f2,f3