Wireless Network and Communication Assignment, Semester 2

This document presents a comprehensive solution to a wireless network and communication assignment. It covers various modulation techniques such as Amplitude Shift Keying, Frequency Shift Keying, and Phase Shift Keying, including their application to binary data conversion. The assignment also includes computations for frequency assignments based on given parameters, the drawing of analog and frequency modulation waveforms, and the creation of a 16 QAM constellation diagram. Furthermore, it explains the error detection process using Cyclic Redundancy Check (CRC) and computes the frame check sequence and transmitted signal using Direct Sequence Spread Spectrum. The solution further differentiates between Infrastructure and ad hoc modes in WLAN, compares TCP and OSI protocols, and explains the advantages of hexagonal cell shapes in cellular communications. References are also provided.

Running head: - WIRELESS NETWORK AND COMMUNICATION
WIRELESS NETWORK AND COMMUNICATION
Name of the Student
Name of the University
Author Note

1WIRELESS NETWORK AND COMMUNICATION
Assignment No-2
1. Convert the binary data “011010” into analog waveforms using following modulation
techniques:
a. Two level Amplitude Shift Keying
b. Two level Frequency Shift Keying

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c. Two level Phase Shift Keying

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d. Differential Phase shift keying

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e. Four level Amplitude Shift Keying

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f. Four level Phase Shift Keying

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g. Eight level Amplitude Shift Keying

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2. With fc = 500 kHz, fd = 25 kHz, and M = 16 (L = 4 bits), compute the frequency
assignments for each of the sixteen possible 4-bit data combinations.
From the given data,
fc = 500 kHz, fd = 25 kHz, and M = 16, L = 4 bits
fi=fc + (2i – 1 – M) *fd
M=2^L =2^4 = 16, M=16
0000 where i=1, f1= 125KHz
0001 where i=2, f2= 175KHZ
0010 where i=3, f3= 225KHZ
0011 where i=4, f4= 275KHz
0100 where i=5, f5= 325KHz
0101 where i=6, f6= 375KHz
0110 where i=7, f7= 425KHz

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0111 where i=8, f8=475KHz
1000 where i=9, f9=525KHz
1001 where i=10, f10= 575KHz
1010 where i=11, f11= 625KHz
1011 where i=12, f12=675KHz
1100 where i=13, f13= 725KHz
1101 where i=14, f14=775KHz
1110 where i=15, f15=825KHz
1111 where i=16, f16=875KHz
The given value can provide the required data rate
1/Tb = 2Lfd = 2*4*25 = 200Kbps
3. Draw the approximate Analog Modulation and Frequency Modulation waveforms in
complete steps for the following signal:

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4. Draw the 16 QAM Constellation Diagram having two different amplitude levels and
eight different phase levels.
5. Explain and draw the Error Detection Process for Cyclic Redundancy Check (CRC).
There are certain number of errors are seen in the communication channel which can
be traced by the help of cyclic redundancy check. The check comprises of series of steps.
Cyclic redundancy check is mainly seen at two ends that is receiver and transmitter. The
whole of the binary data conversion where binary conversion is seen along with k-1 zeros. As
soon as process module 2 binary division is done by with the process of the given key. The
given data is completely made available from the stored data containing the value. The data
added is completely available from the given data and is seen at the side of receiver. The
overall value of receiver is mainly done by the value of 1-bits and completely send to the
transmitter.

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6. Compute the frame check sequence for the following information:
Message = 10111100, Pattern = 11011