ENG434S1: Core Skills and Electronics - Assessed Exercise Problems

This document presents a comprehensive solution to an assessed exercise from the ENG434S1 Core Skills and Electronics course. The assignment is divided into two sets. Set 1 focuses on analyzing a rainwater capture and storage system, requiring the conversion of precipitation data from inches to ...Read More

Set 1
Problem 1
clc
a = [ 4.5 4.61 3.26 1.46 0.7 0.16 0 0.06 0.12 0.12 1.12 3.16 4.56 ] ;
display ('The data in inches:');
display ( a );
b = a * 0.0254;
display ('The data in meters:');
display ( b );
s=0;
for (i= 1:12)
s = s + b(i);
end
v = s * 40.25 * 1000000;
vl = v * 1000;
vg = vl/3.78;
display (' Volume in litres:');
display (vl);
display (' Volume in gallons:');
display (vg);
vtl = s * 10 * 30 * 0.3048 * 0.3048 *1000;
vtg = vtl / 3.78;
display ('amount of rain water collected by the system in a year in
litres:');
display (vtl);
display ('amount of rain water collected by the system in a year in
gallons:');
display (vtg);
du = [ 8.8 10 8.2 0.7 1.2 4 10.8 1.6 ] ;
display ('Daily usage in gallons: ');
display (du);
dl = du * 3.78 ;
display ('Daily usage in litres: ');
display (dl);
dy = dl * 365 ;
display ('Yearly water usage in litres for each activity: ');
display (dy);
s1=0;
for (j= 1:8)
s1 = s1 + dl(j);
end
yu = s1 * 365 ;
display (' Yearly Water usage of 1 person');
display (yu);

Output:
The data in inches:
a =
Columns 1 through 12
4.5000 4.6100 3.2600 1.4600 0.7000 0.1600 0 0.0600 0.1200 0.1200 1.1200
3.1600
Column 13
4.5600
The data in meters:
b =
Columns 1 through 12
0.1143 0.1171 0.0828 0.0371 0.0178 0.0041 0 0.0015 0.0030 0.0030 0.0284
0.0803
Column 13
0.1158
Volume in litres:

vl =
1.9701e+10
Volume in gallons:
vg =
5.2118e+09
amount of rain water collected by the system in a year in litres:
vtl =
1.3642e+04
amount of rain water collected by the system in a year in gallons:
vtg =
3.6089e+03
Daily usage in gallons:
du =

8.8000 10.0000 8.2000 0.7000 1.2000 4.0000 10.8000 1.6000
Daily usage in litres:
dl =
33.2640 37.8000 30.9960 2.6460 4.5360 15.1200 40.8240 6.0480
Yearly water usage in litres for each activity:
dy =
1.0e+04 *
1.2141 1.3797 1.1314 0.0966 0.1656 0.5519 1.4901 0.2208
Yearly Water usage of 1 person
yu =
6.2500e+04

Set 1
Problem 2
clc
vs = 0.01;
c = 0.00001;
r1 = 10000;
r2 = 1000;
r3 = 100;
t = 0 : 0.001 : 0.2;
x1 = -t/(r1*c);
v1 = vs * ( 1 - exp ( x1 ));
plot (t,v1,'m');
hold on;
x2 = -t/(r2*c);
v2 = vs * ( 1 - exp ( x2 ));
plot (t,v2,'g');
hold on;
x3 = -t/(r3*c);
v3 = vs * ( 1 - exp ( x3 ));
plot (t,v3,'c');
hold on;
legend ('r1=10k','r2=1k','r3=0.1k');
title('Output Voltage versus time');
hold off;
grid on;
Output:

Set 2
Problem 1
clc
ilight = 0.5;
idark = 0.0000006;
vt = 0.026;
x = 0.3 / 0.026 ;
p = 1;
s=1;
for (i = 1:4)
p = p * x;
q = factorial(i);
r = p / q;
s = s + r;
end
isolar = ilight + idark - (idark * s);
display('Till 5 terms:');
display (isolar);
p1 = 1;
s1=1;
for (j = 1:19)
p1 = p1 * x;
q1 = factorial(j);
r1 = p1 / q1;
s1 = s1 + r1;
end
isolar = ilight + idark - (idark * s1);
display('Till 20 terms:');
display (isolar);
Output:
Till 5 terms:
isolar =
0.4994
Till 20 terms:
isolar =
0.4394

Set 2
Problem 2
clc
c = [ 0.1 , 0 , 0 , 0 ; 0.75 , 0.05 , 0 , 0 ; 0 , 0.9 , 0.05 , 0;0 , 0 ,
0.9 , 0.05 ];
y = [ 500 ; 400 ; 300 ; 280 ];
b = [ 1000 ; 200 ; 0 ; 0];
for k = 1:10
y = c*y + b;
display (y);
s = sum(y);
bar (k,s);
hold on;
end
Output
y =
1050
595
375
284
y =
1.0e+03 *
1.1050
1.0173
0.5543
0.3517

y =
1.0e+03 *
1.1105
1.0796
0.9432
0.5164
y =
1.0e+03 *
1.1110
1.0869
1.0188
0.8747
y =
1.0e+03 *
1.1111
1.0876

1.0291
0.9607
y =
1.0e+03 *
1.1111
1.0877
1.0303
0.9742
y =
1.0e+03 *
1.1111
1.0877
1.0305
0.9760
y =
1.0e+03 *

1.1111
1.0877
1.0305
0.9762
y =
1.0e+03 *
1.1111
1.0877
1.0305
0.9762
y =
1.0e+03 *
1.1111
1.0877
1.0305
0.9762