Financial Mathematics and Business Calculations Assignment
VerifiedAdded on Β 2023/04/23
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Homework Assignment
AI Summary
This document presents a comprehensive solution to a financial mathematics assignment. The assignment covers a range of topics, including converting decimals and fractions to percentages, and vice versa. It also delves into various financial calculations such as simple and compound interest, and markups. The solutions demonstrate the application of financial formulas to determine amounts invested, interest earned, and break-even points. Furthermore, the assignment explores markup calculations based on cost and retail prices, and the impact of markdowns on selling prices. The solutions provided are detailed and step-by-step, providing a thorough understanding of the financial concepts involved.

Section A
Q1
a)3.72 =372
100 = 372%
b)88.12
100 =88.12%
c)0.125
100 =0.125%
d)656.3
100 =656.3%
e)789
100=789%
Q2
a)3
7 π‘π πππππππ‘ =
3
7 β 100%
=42.85%=4285
100
b) 6
20 = 30%
c)13
5 = 8
5
=1.6=160%
d)1
9 = 11.11%
e)28
3 = 9.33 = 933%
Q3
a)54%=0.54
b)2.38%=0.0238
c)0.00065
d)681
4 % = 273
4 % = 68.25%
=0.6825
e)2.89%=0.0289
Q4
a)35%= 7
20
b)15.22%=761
50 =1511
50
c)156%=114
25
d)3%= 3
100
Q1
a)3.72 =372
100 = 372%
b)88.12
100 =88.12%
c)0.125
100 =0.125%
d)656.3
100 =656.3%
e)789
100=789%
Q2
a)3
7 π‘π πππππππ‘ =
3
7 β 100%
=42.85%=4285
100
b) 6
20 = 30%
c)13
5 = 8
5
=1.6=160%
d)1
9 = 11.11%
e)28
3 = 9.33 = 933%
Q3
a)54%=0.54
b)2.38%=0.0238
c)0.00065
d)681
4 % = 273
4 % = 68.25%
=0.6825
e)2.89%=0.0289
Q4
a)35%= 7
20
b)15.22%=761
50 =1511
50
c)156%=114
25
d)3%= 3
100
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e)45%= 9
20
Q5)
a) y=3x+2, x=5
=y=5*3+2
=17
b) x=2π2 β 3π + 6, π = β2
=20
c) y=7x-5, y=2.73
x=1.104
d) π¦ = π₯ β 5π₯2 + 3, π₯ = 2.304
y=-21.23
e) x=y-3x, y=5
x=5-3x
x=5
4
=1.25
Section A
Q1)
a)
i) cost price =5000
Mark up based on cost price= π ππππππ πππππβπππ π‘ πππππ
πππ π‘ πππππ x100
Let selling price be X
πβ5000
5000 = .2
X-5000=1000
X=6000RM
ii) mark up based on retail price=π ππππππ πππππβπππ π‘ πππππ
π ππππππ πππππ x100
=πβ5000
π = 0.2
X-5000=.2X
.8X=5000
X=6250RM
20
Q5)
a) y=3x+2, x=5
=y=5*3+2
=17
b) x=2π2 β 3π + 6, π = β2
=20
c) y=7x-5, y=2.73
x=1.104
d) π¦ = π₯ β 5π₯2 + 3, π₯ = 2.304
y=-21.23
e) x=y-3x, y=5
x=5-3x
x=5
4
=1.25
Section A
Q1)
a)
i) cost price =5000
Mark up based on cost price= π ππππππ πππππβπππ π‘ πππππ
πππ π‘ πππππ x100
Let selling price be X
πβ5000
5000 = .2
X-5000=1000
X=6000RM
ii) mark up based on retail price=π ππππππ πππππβπππ π‘ πππππ
π ππππππ πππππ x100
=πβ5000
π = 0.2
X-5000=.2X
.8X=5000
X=6250RM

b)
90 shirts at RM20
10% shirts at RM15
That is 9 shirts at RM15
9x15=135
Remaining 85 shirts sold at RM20
81x20=1620RM
πβ1620
1620 x 100=75
X=2835
πβ135
135 x 100=75
Y=236.25
Total = X+Y
= 2835+236.25
=RM3071.25RM
Q2)
a)
Let X is the amount invested at 10% annum and 10000-X is the amount invested 7%
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
Total amount after 1 years= 10820
10820 = X (1+.1x1) + (10000-X)(1+.07x1)
10820 = 1.1X + 10700 - 1.07X
10820 =0.03X + 10700
0.03X = 10820 - 10700
X = 4000RM
Amount deposited at 10% is 4000RM and amount deposited at 7% is 10000-4000=6000RM
90 shirts at RM20
10% shirts at RM15
That is 9 shirts at RM15
9x15=135
Remaining 85 shirts sold at RM20
81x20=1620RM
πβ1620
1620 x 100=75
X=2835
πβ135
135 x 100=75
Y=236.25
Total = X+Y
= 2835+236.25
=RM3071.25RM
Q2)
a)
Let X is the amount invested at 10% annum and 10000-X is the amount invested 7%
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
Total amount after 1 years= 10820
10820 = X (1+.1x1) + (10000-X)(1+.07x1)
10820 = 1.1X + 10700 - 1.07X
10820 =0.03X + 10700
0.03X = 10820 - 10700
X = 4000RM
Amount deposited at 10% is 4000RM and amount deposited at 7% is 10000-4000=6000RM
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b)
i)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P =500 ,r=.12, t=1
A =500 x (1+.12x1)
= 560
Interest for 1 year =560 -500
=60RM
ii)
P=500 r= 0.12 t=5
Amount after 5 years= A=P (1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
A= 500 x (1+.12x5)
=800RM
Interest for 5 years = amount after 5 years β principal amount
=800-500
= 300RM
Q3)
Markdown percent on tv set is 10%
Retail price is RM 900
Let old selling price = X
πππ π ππππππ πππππβπππ€ π ππππππ πππππ
πππ π ππππππ πππππ = mark down
i)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P =500 ,r=.12, t=1
A =500 x (1+.12x1)
= 560
Interest for 1 year =560 -500
=60RM
ii)
P=500 r= 0.12 t=5
Amount after 5 years= A=P (1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
A= 500 x (1+.12x5)
=800RM
Interest for 5 years = amount after 5 years β principal amount
=800-500
= 300RM
Q3)
Markdown percent on tv set is 10%
Retail price is RM 900
Let old selling price = X
πππ π ππππππ πππππβπππ€ π ππππππ πππππ
πππ π ππππππ πππππ = mark down
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πβ900
π =0.1
X-900 = 0.1X
0.9 X = 900
X=1000
WORKSHEET 2
Q1
a)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P= 800RM r=0.06 t=1
Amount after 1year = 800x(1+0.06x1)
= 848RM
Amount of interest = amount after 1 year- principal amount
= 848-800
= 48 RM
b)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P= 1500RM t=6 r=0.11
Amount after 6 years = 1500 x (1+0.11x6)
= 2490RM
Amount of interest= Amount after 6 years- principal amount
= 2490-1500
= 990RM
π =0.1
X-900 = 0.1X
0.9 X = 900
X=1000
WORKSHEET 2
Q1
a)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P= 800RM r=0.06 t=1
Amount after 1year = 800x(1+0.06x1)
= 848RM
Amount of interest = amount after 1 year- principal amount
= 848-800
= 48 RM
b)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P= 1500RM t=6 r=0.11
Amount after 6 years = 1500 x (1+0.11x6)
= 2490RM
Amount of interest= Amount after 6 years- principal amount
= 2490-1500
= 990RM

c)
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P=2000 r=0.14 t=7
Amount after 7 years = 2000(1+0.14x7)
=3960RM
Amount of interest = Amount after 7 years βprincipal amount
=3960-2000
= 1960RM
Q2)
A=P(1+rt)
A = simple interested amount
P = principal amount
r= interest rate in decimals
t= number of years
Total amount to repaid= 4000x(1+0.1x4)
=5600RM
Amount of interest repayable = total amount to paid β principal amount
= 5600-4000
= 1600RM
There fore
a) =1600RM
b) =5600RM
Q3
A=P(1+rt)
A = simple interested amount
P= principal amount
A=P(1+rt)
A = simple interested amount
P= principal amount
r= interest rate in decimals
t= number of years
P=2000 r=0.14 t=7
Amount after 7 years = 2000(1+0.14x7)
=3960RM
Amount of interest = Amount after 7 years βprincipal amount
=3960-2000
= 1960RM
Q2)
A=P(1+rt)
A = simple interested amount
P = principal amount
r= interest rate in decimals
t= number of years
Total amount to repaid= 4000x(1+0.1x4)
=5600RM
Amount of interest repayable = total amount to paid β principal amount
= 5600-4000
= 1600RM
There fore
a) =1600RM
b) =5600RM
Q3
A=P(1+rt)
A = simple interested amount
P= principal amount
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r= interest rate in decimals
t= number of years
P= 5000 t=3 A=6125 r=?
6125=5000(1+3xr)
1.225=1+3r
.225=3r
r=0.075
R=7.5%
WORKSHEET 3
Q1
a) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P= 1000 r=0.07 n=1 t=8
A= 1000(1 +.07
1 )8π₯1
= 1718.186RM
b) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=2500 r=0.09 n=2 t=10
A=2500(1 +0.09
2 )2β10
=6029.28RM
c) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
t= number of years
P= 5000 t=3 A=6125 r=?
6125=5000(1+3xr)
1.225=1+3r
.225=3r
r=0.075
R=7.5%
WORKSHEET 3
Q1
a) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P= 1000 r=0.07 n=1 t=8
A= 1000(1 +.07
1 )8π₯1
= 1718.186RM
b) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=2500 r=0.09 n=2 t=10
A=2500(1 +0.09
2 )2β10
=6029.28RM
c) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
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n = number of times compounding per year
P=42000 n=4 r=0.0775 t=8
A=42000(1 +0.0775
4 )4β8
=57094.32RM
d) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=180000 r=0.09 n=12 t=6.25
A= 180000(1 +0.09
12 )12β6.25
=315247.47RM
e) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=150000 r=0.12 n=365 t=3
A=150000(1 +0.12
365)365β3
=214986.6921RM
Q2
A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
A=3500 P=2000 n=2 t=5 r=?
3500 = 2000(1 +π
2)2β5
1.0575=π
2 + 1
r=.115
r=11.5%
P=42000 n=4 r=0.0775 t=8
A=42000(1 +0.0775
4 )4β8
=57094.32RM
d) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=180000 r=0.09 n=12 t=6.25
A= 180000(1 +0.09
12 )12β6.25
=315247.47RM
e) A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
P=150000 r=0.12 n=365 t=3
A=150000(1 +0.12
365)365β3
=214986.6921RM
Q2
A=π(1 +π
π)ππ‘
A = Compound interested amount
P = principal amount
r = interest rate in decimals
t = number of years
n = number of times compounding per year
A=3500 P=2000 n=2 t=5 r=?
3500 = 2000(1 +π
2)2β5
1.0575=π
2 + 1
r=.115
r=11.5%

WORKSHEET 4
Q1) selling price per unit=20
Variable cost per unit= 10
Contribution margin= Selling price per unit-variable cost per unit
=20-10
=10
Q2) Variable cost per unit 18
Fixed cost =RM 20000
Revenue per unit =RM35
Break even point = πππ₯ππ πππ π‘
πππ£πππ’π πππ π’πππ‘βπ£πππππππ πππ π‘
=20000
35β18
=RM1176.4705
Q1) selling price per unit=20
Variable cost per unit= 10
Contribution margin= Selling price per unit-variable cost per unit
=20-10
=10
Q2) Variable cost per unit 18
Fixed cost =RM 20000
Revenue per unit =RM35
Break even point = πππ₯ππ πππ π‘
πππ£πππ’π πππ π’πππ‘βπ£πππππππ πππ π‘
=20000
35β18
=RM1176.4705
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