Detailed IPv4 Subnetting Assignment Solution for Network Design

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Added on  2022/07/28

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Homework Assignment
AI Summary
This document presents a solution to an IPv4 subnetting assignment, addressing the design of a variable-length addressing scheme for a given network address (129.99.0.0/16). The solution details the subnetting requirements for various departments and locations within an organization, including Customer Services, Engineering, Sales, IT Support, and HQ, across multiple cities (City I, City II, City III, and City IV). The solution provides the number of users, subnet masks, Network IDs, Broadcast IPs, and valid IP ranges for each department, demonstrating the application of subnetting principles to efficiently allocate IP addresses. Furthermore, the document explains the rationale behind the subnet mask selection for each scenario based on the number of required hosts and includes calculations to determine the number of usable hosts per subnet. The solution also includes an explanation on how to calculate the number of hosts based on the subnet mask.
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AS No. Location Department The Number
of Users
Subnet Mask NewtworkID BroadCastIP
AS1 City I
Customer
services in
Building A
260 255.255.254.0 129.99.0.0 129.99.1.255
Engineering
in Building B
600 255.255.252.0 129.99.4.0 129.99.7.255
Sales in
Building C
140 255.255.255.0 129.99.2.0 129.99.2.255
City II Sales 70 255.255.255.128 129.99.3.0 129.99.3.127
AS2 City III Sales 90 255.255.255.128 129.99.3.128 129.99.3.255
IT support 24 255.255.255.224 129.99.12.0 129.99.12.31
AS3 City IV
HQ in A
Block
1,000 255.255.252.0 129.99.8.0 129.99.11.255
Finance in B
Block
100 255.255.255.128 129.99.12.128 129.99.12.255
Sales in C
Block
130 255.255.255.0 129.99.13.0 129.99.13.255
Subnet , is smallnumber of IP within a large network
The subnet masks can be as shown below
25 26 27 28 29 30 31 32
128 192 224 240 248 252 254 255
128 64 32 16 8 4 2 1
00000000. 00000000. 00000000. 00000000 32 bits
8 16 24
129.99.0.1 - 129.99.255.254 the range of the network to be subnetted
The cutomer department in city 1 requires 260 hosts in its network this means that the sunet
mask will have less than 24 which supportd 256 hosts
23 is found in octate 3 thus the subnet will have 255.255.254.0 with 512 hosts has show
above.
32-23=9. 2^9 =512 hosts.
Building 2 B requires 600 hosts
The cutomer department Bin city 1 requires 600 hosts in its network this means that the sunet
mask will have less than 22 which supportd 600 hosts
23 is found in octate 3 thus the subnet will have 255.255.252.0 with 1000 hosts has show
below.
32-22=10. 2^9 =1024 hosts.
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Sales in city 1
The sales department in city 1 require 140 hosts in its network this means that the sunet mask
will be 24 which supportd 256 hosts
23 is found in octate 3 thus the subnet will have 255.255.255.0 with 256 hosts has show
above.
32-24=8. 2^8 =256 hosts.
sales
The sales department in city 1 require 70 hosts in its network will be found in subnet 25 which
provides 128 hosts
25 is found in octate 3 thus the subnet will have 255.255.255.0 with 128 hosts has show
above.
32-25=7. 2^9 =128 hosts.
sales
The sales department in city 2 require 90 hosts in its network will be found in subnet 25 which
provides 128 hosts
25 is found in octate 3 thus the subnet will have 255.255.254.0 with 128 hosts has show
above.
32-25=7. 2^9 =128 hosts.
The IT support in city 1 require 32hosts in its network will be found in subnet 27 which provides
32 hosts
27 is found in octate 4 thus the subnet will have 255.255.255.224 with 32 hosts has show
above.
32-27=5. 2^5 =32 hosts.
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