MITS5003 Wireless Networks & Communication Assignment 1

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MITS5003 – Wireless networks &
Communication
Assignment No. 1

Contents
Question 1........................................................................................................................................3
Question 2........................................................................................................................................4
Question 3........................................................................................................................................5
Question 4........................................................................................................................................6
Question 5......................................................................................................................................10
Question 6......................................................................................................................................11
Question 7......................................................................................................................................12
Question 8......................................................................................................................................13
Question 9......................................................................................................................................14
References......................................................................................................................................15

Question 1
The question helps in differentiating between the two layers of the TCP i.e. IP and Network
Access Layer. The TCP protocol is also used as the network (Goralski, 2017) model. It stands for
Transmission Control protocol which is used for maintaining the communication between the
network devices.
Internet protocol Layer Network Access Layer
It is the second layer of the TCP protocol. It is the first layer in the TCP/IP model.
IP datagrams containing the address of the
destination and the source is been converted as
the data packets. This layer is also responsible
for routing the datagrams.
It helps in providing detail of data
transmission over the network. For example, it
helps in describing the bit synchronization and
how they are signalled electronically.
The various protocols which are included in
this layer are ICMP, ARP and RARP.
The various protocols which are included in
this layer are Frame Relay, Token Ring and
Ethernet.

Question 2
Given Scenario is to maintain the communication between the French and Chinese prime
minister both know their native language only. Due to unavailability offhand translator, they
couldn’t understand other language and hence the English translator present will help them to
communicate two prime minister. The following below diagram will show their telephonic
conversation via English Translator.
Description
 The interaction between them happen in the following way
 French prime minister conveys the message to French Translator.
 French translator sends this message to the Chinese translator over the telephone system
in English.
 The Chinese translator conveys the message to the Chinese prime Minister
 Hence this message gets exchanged over the telephone.

Question 3
to find the maximum amplitude, frequency and time period and phase for each of the following
given waveform. Given X-axis represent the time and Y-axis represent the amplitude.

Figure 1: waveform 1
Figure 2: waveform 2
Figure 3: waveform 3
Question 4
a. 3𝑆𝑖𝑛(2𝜋(200)𝑡)
Amplitude - 15
Frequency – .33 Hz
Time period – 3 sec
Phase – 0
Amplitude - 4
Frequency - .153 Hz
Time period – 6.5 sec
Phase - 0
Amplitude – 7.5
Frequency - .444 Hz
Time period – 2.25 sec
Phase – 90

Amplitude – 3
Frequency – 200 Hz
Time period – .005 sec
Phase – 0
Figure 4: y = 3𝑆𝑖(2𝜋(200)𝑡)
b. 14𝑆𝑖𝑛(2𝜋(50)𝑡 + 90)
Amplitude – 14
Frequency – 50 Hz
Time period – .02
Phase – 90

Figure 5 : y = 14𝑆𝑖(2𝜋(50)𝑡 + 90)
c. 4𝑆𝑖𝑛(650𝜋𝑡 + 180)
Amplitude – 4
Frequency – 325 Hz
Time period – 0.003 sec
Phase – 180

Figure 6 : y = 4𝑆𝑖(650𝜋𝑡 + 180)
d. 6𝑆𝑖𝑛(700𝜋𝑡 + 270)
Amplitude – 6
Frequency – 350 Hz
Time period – 0.002
Phase – 270

Figure 7 : y = 6𝑆𝑖(700𝜋𝑡 + 270)

Question 5
It is asked in the question to calculate the isotropic free space loss
Given frequency is 6 GHz = 6 x 10 9 Hz
Given the shortest path between satellite (Panaretos and Zemel, 2016) and earth is 35863 km
converting into meter will give 35.863 x 106 m.
By using the formula – (loss) dB = 20 log 10 (4R𝜋/wavelength) ……. (i)
Wavelength can be calculated by = c / f = 3 x 10 8 / 6 x 10 9 = 0.495 m
Substituting the value in equation (i) we can calculate loss dB as 99. 68 dB

Question 6
Given signal wave equation (𝑡) = 5 sin(100𝜋𝑡) + sin(300𝜋𝑡) + sin(600𝜋𝑡)
It is asked to calculate fundamental Frequency, spectrum, bandwidth and the channel capacity.
Fundamental Frequencies can be calculated by w/2
W = 100 W= 300 W = 600
W/2 = 50 W/2 = 150 W/2= 300
Bandwidth can be calculated by adding all the fundamental frequencies which are (300) + (150)
+ (50) = 500 MHz.
Hence 50, 150 and 300 are the fundamental frequencies.
Using Nyquest criteria for calculating (Lanczos, 2016) the channel capacity using M = 2, 4, 8,
where M is the number of levels.
As the Nyquest theorem says, to gain adequate signals the bit rate must be twice the bandwidth,
and hence, channel capacity for M = 2 is 2 * 500 ( log 2)2 = 1000 same can be calculated for 4 as
2000 and for M = 8 channel capacity is 4000 bits per second.