MXB106 Linear Algebra Workbook 2 - Semester 1, 2019 - Solution

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Homework Assignment
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This document presents the solutions to the Linear Algebra Workbook 2 for the MXB106 course, Semester 1, 2019. The assignment focuses on two main problems. The first problem involves finding the row reduced echelon form of a given matrix, determining the number of linearly independent columns, and calculating the null space. The second problem involves solving a system of linear equations using elementary row operations, determining the basis for the null space, and exploring vector orthogonality. The solutions include detailed steps, explanations, and calculations to demonstrate the methods used to solve each problem. The solutions are presented in a clear and concise manner, providing a comprehensive guide to understanding the concepts of linear algebra and solving related problems. The document covers topics such as row reduction, null space, and vector orthogonality, providing a complete solution for the assignment.
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Solution 1: Given matrix is .
Let’s first find the row reduced echelon form of above matrix. Perform elementary row
operations.
Apply
Apply
a): From above rref(A) matrix, it is observe that the 1st and 3rd columns contains pivot
elements. So, these two columns are linearly independent. And hence, total number of
linearly independent column of matrix A is 2.
b): Solve that is we need to solve
. This gives,
So,
Hence, basis for the null space of A is .
c): The vector b is the sum of the four columns of A that is
Then the general solution to is
, where are arbitrary.
Solution 2: Given vector
And the matrix
Let’s solve
The augmented matrix is
Let’s perform elementary row operations.
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From last matrix we get
So,
Hence, basis for null space is .
b): The null space of A is . Let be the vector orthogonal to null
space of A, that is
Solve we get the set of orthogonal vector as
Now consider a vector fro null space of A as and a vector from orthogonal set
of vector as . Given
Suppose
So,
Since, above system is inconsistent. So we can not the sum of a vector in the null space of
A and a vector orthogonal to the null space of A.
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