COIT20261 Network Routing and Switching Assignment - Term 1, 2018

This document presents a solved assignment on network routing and switching (COIT20261), covering key concepts such as IP addressing, subnetting, and network analysis. The assignment includes calculations of network addresses, subnet masks, and host ranges for classless address blocks. It also delves into the use of Wireshark for packet analysis, identifying network problems, and interpreting the 'NETSTAT -aon' command output. Furthermore, the solution demonstrates the application of the traceroute command for determining network paths. The solution is comprehensive, providing detailed explanations and calculations to facilitate understanding of network routing and switching principles.

COIT20261 Network Routing and Switching (Term 1, 2018)
Assignment item —Written Assessment-1
First Name: _________________________ Last Name: _________________________
Student ID: __________________________
Question Number Mark
allocated
Mark
earned
Question 1: (3 marks) 3
a)
b)
c)
The network address for the classless address block of 154.78.177.3/27 is
154.78.177.0/27
Binary representation of the IP address - 10011010. 01001110.
10110001. 000 00011
Binary representation of subnet mask - 11111111. 11111111.
11111111. 111 00000
Network address - 10011010. 01001110.
10110001. 000 00000
For the calculation of the network address the address block is
converted into binary notation, then the subnet is calculated by
performing a bit wise AND operation on the host address and the
subnet. The subnet address is found for adding the hosts.
The direct broadcast address for the classless address block 154.78.177.3/27
is 154.78.177.31.
The broad cast address is identified by all the 1s.
10011010. 01001110. 10110001. 000 11111
The range available for the hosts to use starts from 154.78.177.1 to
154.78.177.30
1 mark
each
item,
total 3

COIT20261 Network Routing and Switching (Term 1, 2018)
Assignment item —Written Assessment-1
For finding the range of the IP address the first host is calculated using the by
identifying all the 0s and a 1 and for finding the last host all 1s and a 0 is used.
Question 2: (8 marks) 8
a) Address - 138.77.216.5 /24
Network address of the block – 138.77.216.0
Binary conversion of 138.77.216.5
10001010.01001101.11011000 .00000101
Binary of the subnet mask 255.255.255.0
11111111.11111111.11111111 .00000000
The network address
10001010.01001101.11011000 .00000000
138.77.216.0 /24
1
b) Subnet No. addresses Subnet address Mask /n
1 32 138.77.216.0 /26
2 32 138.77.216.64 /26
3 16 138.77.216.128 /27
4 16 138.77.216.160 /27
5 16 138.77.216.160 /27
6 16 138.77.216.224 /27
6
c) It is not possible to create another subnet for assigning more 1024 address to
the network address 138.77.216.0 /24. For the /24 subnet 254 maximum
number of hosts can be accommodated and among them 128 number of IP
address are allocated to the six different subnet. There are 126 number of IP
1

COIT20261 Network Routing and Switching (Term 1, 2018)
Assignment item —Written Assessment-1
address remaining that is insufficient because the requirement is 1024
addresses.
Question 3: (4 marks) 4
a)
i)
ii)
iii)
iv)
The interface of the wireshark is divided into three horizontal window and the
first part contains the list of data packets that are captured by selecting the
start capture option in the menu bar of wireshark. The time, source,
destination, protocol, length and the information is described in the first
horizontal window. The second section consists of details of the packet and it
provides the details of the packet that is selected from the first section of the
window. Lastly, the third section provides the details of the content in raw
data format and it is known as the packet byte pane.
From the frame 3 the brand of the computer used for launching the scan and
the IP address of the computer can be identified. The brand identified is
Hewlett and the IP address of the computer was 138.77.216.88. The details of
the computer and the IP address can be found from the packet details section
and expanding the Ethernet II option and the IPv4 address.
Frame 4- A hello message is sent from the server to the client
Frame 5 – The digital certificate is verified at the clients end and
Frame 6 – Server hello message done is sent from the server to the client
The two specific network problem that can be troubleshooted using the
wireshark tool are given below:
a. Identification of the source of the errors in the network
b. Identification of the source of traffic in the network and block
the host for securing the network.
.5 mark
each
item,
total 2
for 3a.
b) 1

COIT20261 Network Routing and Switching (Term 1, 2018)
Assignment item —Written Assessment-1
Description of the column heading of ‘NETSTAT –aon’
Proto – It defines the protocol used for the transmission of the data in the
network
Local Address, Foreign Address – It is used for the listing the source and the
destination address between whom the data is sent in the network. The local
address is given for the host running the NETSTAT command and foreign
address is for the other nodes connected in the network.
State – It is used for demonstration of the socket state.
PID – It shows the process ID and it can be used for finding the owner of the
process and finding the program in the network.
LISTENING – If the state is listening then it means that the host is waiting of an
external agent for connection establishment
ESTABLISHED – if the device have an ESTABLISHED state it means that the
device is ready for communication, and
CLOSED_WAIT – it means that the connection between the remote and the
client host has terminated and the local programs are not updated.
c) 1