Maths Assignment: Proofs of Equations, Series, and Relation Properties

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Added on  2023/01/16

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Homework Assignment
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This assignment presents solutions to several mathematical problems. The first solution provides a proof related to an integer, while the second solution simplifies an expression and proves a property related to even integers. It also includes the concept of the cross product and the derivative of a function. Furthermore, the assignment explores solving equations and presents a parametric form for the solution. Finally, the assignment defines the set of rational numbers and concludes with a proof demonstrating that a defined relation is a partial order, covering reflexivity, anti-symmetry, and transitivity. This assignment provides valuable insights into equation manipulation, series, and fundamental mathematical concepts.
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Solution 1: To prove for an integer ,
Consider left hand side
Simplify further we get,
Hence, . This completes the proof.
Now, let’s simplify .
We know that,
Differentiating with respect to x we get,
Substitute we get,
Solution a: Suppose that is an integer such that . This implies
that
And
For some integers
Subtract equation (1) from equation (2) we get,
Suppose we get,
Since, and are the two consecutive integers and we know that product of two
consecutive integer is divisible by 2. That is must be multiple of 2, and hence
.
Solution b: To prove that for an even integer n.
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By Euclid algorithm, . Since 2 is second smallest prime
number and n is even this implies that is odd. We know that the gcd of a prime
number and any number is 1.
Hence
Therefore,
Solution: Given that A relation is defined on R by is and only if for some
integer
To prove that is partial order.
We know that is partial order if the relation is reflexive, anti-symmetric and transitive.
Reflexive: For , is true for some integer k. hence relation R is reflexive.
Anti-symmetric: Suppose and this implies that
Hence, relation is Anti-symmetric
Transitive: Suppose . This implies that
Hence, the relation is Transitive.
Since, the given relation is reflexive, anti-symmetric and transitive. Therefore the relation
is partial order. This completes the proof.
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