Quantitative Business Analysis: Homework Assignment Solutions

Verified

Added on  2022/09/12

|9
|478
|23
Homework Assignment
AI Summary
This assignment provides solutions to a series of quantitative business analysis problems. The solutions cover topics such as optimal solutions, sensitivity analysis, linear programming, and break-even analysis. The document includes detailed explanations and calculations for each problem, including the use of graphical representations and algebraic equations. Specific problems addressed involve maximizing profit, determining the optimal number of units to produce, and identifying break-even points. The solutions also analyze the impact of changes in variables, such as selling prices and production costs, on the overall financial outcomes. The assignment aims to help students understand and apply quantitative techniques to solve real-world business challenges, providing a comprehensive guide for understanding the key concepts.
Document Page
Quantitative Business Analysis
[DATE]
tabler-icon-diamond-filled.svg

Paraphrase This Document

Need a fresh take? Get an instant paraphrase of this document with our AI Paraphraser
Document Page
Problem 7.28
(a) Optimal solution change
Maximize profit=$ 3 X + $ 2Y
Subject to constraints
2 X +Y 150
2 X +3 Y 300
Graph
Intersection point D
2 X +Y 150
2 X +3 Y 300
X =37.5 ,Y =75 (Optimal solution)
Maximum (37.5, 75) = 3 *37.5 + 2*75 = 262.5 (Optimal solution)
1
Document Page
When profit per unit of changes to $4.50
Maximum profit = $4.5 X + $2 Y
In this case, the slope of iso-profit line would change.
Maximum (75,0) = 4.5*75 + 2*0 = 337.5(Optimal solution)
(b) Profit per unit Y changes to $3
Maximum profit = $3X + $3Y
Maximum (37.5, 75) = 3 *37.5 +3*75 = 337.5
2
Document Page
Problem 7-29
Optimal solution change
Maximize profit=$ 4 X + $ 6 Y
Subject to constraints
X +2 Y 8
6 X + 4 Y 24
Graph
D: 2 X +4 Y =82=16
6 X + 4 Y =2 4
X =2 ,Y =3
3
tabler-icon-diamond-filled.svg

Paraphrase This Document

Need a fresh take? Get an instant paraphrase of this document with our AI Paraphraser
Document Page
Maximum value (2,3) = $4*2 + $6*3 =$26 (Optimal solution)
Problem 7 – 18
Linear programming model
Let U is course offered in undergraduate and G is course offered in graduate.
Objective function
Min (Z) = 2500 U + 3000 G
Subject to constraints
Undergraduate: 1U + 0 G >= 30
Graduate: 0 U +1 G > =20
Faculty: U +G > =60
U, G >0 Non negativity constraints.
Solver output
4
Document Page
Answer Report
Sensitivity Report
5
Document Page
Limit Report
Hence, U is course offered in undergraduate and G is course offered in graduate would be
$40 and $20 respectively. Minimum faculty salaries would be $160,000.
Problem 1-14
(a) Total variable cost =?
Total revenue = 20*15 =$300
Total variable cost = 20*8 =$160
(b) Number of shirts and revenue at break-even =?
Breakeven units= 350
158 =50 units
Breakeven revenue=5015=$ 750
6
tabler-icon-diamond-filled.svg

Paraphrase This Document

Need a fresh take? Get an instant paraphrase of this document with our AI Paraphraser
Document Page
Problem 1-15
Variable cost = $20
Selling price = $50
Cost to rent a booth at the fair = $150
Number of units must Ray sell to break-even =?
At break-even
Cost = Revenue
150 + 20 C = 50 C
C = 5
Hence, 5 units must Ray sell to break-even.
Problem 1-16
Variable cost of production = $15 per unit
Break-even point =?
Cost of producing y handcrafted yards then,
Cost of making y handcrafted yards = 15 y + 150
Revenue from y handcrafted yards = 50 y
At break-even
15 y + 150 = 50 y
35 y = 150
Y = 4.29
Break-even point would be 5.
7
Document Page
Problem 1-17
Number of units to sell at break-even (x) =?
Now,
(400 + 3x) + 1000 = 5x
1400 + 3x = 5x
1400 =5x-3x
1400 = 2x
X = 700
Therefore, the number of units to sell programs at break-even would be 700.
8
chevron_up_icon
1 out of 9
circle_padding
hide_on_mobile
zoom_out_icon
[object Object]