Statistics Assignment: Analyzing Housing, Mutual Funds, and Returns
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Homework Assignment
AI Summary
This statistics assignment analyzes financial data, focusing on descriptive and inferential statistics. Part A examines fixed interest rates, comparing periods before and after 2000, using box plots, descriptive statistics, and the empirical rule to assess distributions, symmetry, and variation. Part B delves into mutual funds, employing hypothesis testing to investigate the relationship between risk and sales charges, the proportion of sales charges in average risk funds, and the impact of higher risk on returns, with a regression analysis to predict returns based on various factors. The assignment includes tables, graphs, and interpretations to support the statistical findings and conclusions.

Running head: STATISTICS
Statistics
Name of the Student:
Name of the University:
Author note:
Statistics
Name of the Student:
Name of the University:
Author note:
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1STATISTICS
Table of Contents
PART A......................................................................................................................................2
PART B......................................................................................................................................4
Answer to the question 1........................................................................................................4
Answer to the question 2........................................................................................................6
Answer to the question 3........................................................................................................6
Answer to the question 4........................................................................................................7
Bibliography...............................................................................................................................9
PART A
Table of Contents
PART A......................................................................................................................................2
PART B......................................................................................................................................4
Answer to the question 1........................................................................................................4
Answer to the question 2........................................................................................................6
Answer to the question 3........................................................................................................6
Answer to the question 4........................................................................................................7
Bibliography...............................................................................................................................9
PART A

2STATISTICS
(i)
Table 1 Summary statistics on fixed rate
0
1
2
3
4
5
6
7
8
9
10
Box Plot on Fixed rate
Figure 1 Box Plot on fixed rate
The mean of the fixed rate is 8.49. The median of the fixed rate is 8.34. Similarly the mode of
the fixed rate is 9.99. Since the mean of the fixed rate is higher than the median. Hence the
(i)
Table 1 Summary statistics on fixed rate
0
1
2
3
4
5
6
7
8
9
10
Box Plot on Fixed rate
Figure 1 Box Plot on fixed rate
The mean of the fixed rate is 8.49. The median of the fixed rate is 8.34. Similarly the mode of
the fixed rate is 9.99. Since the mean of the fixed rate is higher than the median. Hence the
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skewness is positive. The value of the skewness is 0.32. The variance, standard deviation and
range of the fixed rate is 0.90, 0.95 and 3.29.
In the 5th month 1990 the higher variation has been seen.
(ii)
1 10 19 28 37 46 55 64 73 82 91 100 109 118 127 136 145 154 163 172 181
0
2
4
6
8
10
12
Fixed rate
Observations
Frequency
Figure 2 Graph on Fixed rate
The empirical rule that is 68-95-99.
At 68%
Mean ± 1* standard deviation
= 8.49± 0.95
= (7.54, 9.44)
At 95%
Mean ± 2* standard deviation
= 8.49± 1.90
skewness is positive. The value of the skewness is 0.32. The variance, standard deviation and
range of the fixed rate is 0.90, 0.95 and 3.29.
In the 5th month 1990 the higher variation has been seen.
(ii)
1 10 19 28 37 46 55 64 73 82 91 100 109 118 127 136 145 154 163 172 181
0
2
4
6
8
10
12
Fixed rate
Observations
Frequency
Figure 2 Graph on Fixed rate
The empirical rule that is 68-95-99.
At 68%
Mean ± 1* standard deviation
= 8.49± 0.95
= (7.54, 9.44)
At 95%
Mean ± 2* standard deviation
= 8.49± 1.90
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= (6.58, 10.39)
At 99%
Mean ± 3* standard deviation
= 8.49± 2.86
= (5.63, 11.35)
Sampling error = 1.65
PART B
Answer to the question 1
Null hypothesis: There is no relationship between risk and sales charge.
Alternative hypothesis: There is a relationship between risk and sales charge.
Table 2 Chi square test
Test statistic = 0.79
= (6.58, 10.39)
At 99%
Mean ± 3* standard deviation
= 8.49± 2.86
= (5.63, 11.35)
Sampling error = 1.65
PART B
Answer to the question 1
Null hypothesis: There is no relationship between risk and sales charge.
Alternative hypothesis: There is a relationship between risk and sales charge.
Table 2 Chi square test
Test statistic = 0.79

5STATISTICS
P-value 0.67
Alpha =0.05
It has been seen that the P-value > alpha. Hence the null hypothesis is not significant.
Thus it may be summarized that is no relationship between risk and sales charge.
Again
Null hypothesis: In average risk funds the sales charge for proportion is 0.50.
Alternative hypothesis: In average risk funds the sales charge for proportion is not 0.50.
Table 3 T-test
WORKING:
N= 76
X = 42
P = 42/76
= 0.55
P-value 0.67
Alpha =0.05
It has been seen that the P-value > alpha. Hence the null hypothesis is not significant.
Thus it may be summarized that is no relationship between risk and sales charge.
Again
Null hypothesis: In average risk funds the sales charge for proportion is 0.50.
Alternative hypothesis: In average risk funds the sales charge for proportion is not 0.50.
Table 3 T-test
WORKING:
N= 76
X = 42
P = 42/76
= 0.55
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P1= 0.50
Z=
p− p 1
√ p 1∗(1− p 1)
n¿
¿
=
0.55−0.50
√ 0.50∗(1−0.50)
76 ¿
¿
= 0.87
SHOW EXCEL: P-value= t.dist.2t(test statistic, df)
It is clear that P-value > alpha (alpha =0.10). Hence the null hypothesis is not
significant. Thus it may be summarized that in average risk funds the sales charge for
proportion is 0.50.
Therefore the percentage of average risk and high risk of sales charge is 50%.
Answer to the question 2
P1= 0.50
Z=
p− p 1
√ p 1∗(1− p 1)
n¿
¿
=
0.55−0.50
√ 0.50∗(1−0.50)
76 ¿
¿
= 0.87
SHOW EXCEL: P-value= t.dist.2t(test statistic, df)
It is clear that P-value > alpha (alpha =0.10). Hence the null hypothesis is not
significant. Thus it may be summarized that in average risk funds the sales charge for
proportion is 0.50.
Therefore the percentage of average risk and high risk of sales charge is 50%.
Answer to the question 2
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Table 5 Confidence interval
Null hypothesis: The mutual fund with higher risk is 50%
Alternative hypothesis: The mutual fund with higher risk is not 50%
The confidence interval is (36.77%, 65.36%). The higher risk of mutual fund lies
within the confidence interval. Hence the null hypothesis is accepted.
Answer to the question 3
Null hypothesis: The 1999 return is not larger than 10% of mean return Q1-2000.
Alternative hypothesis: The 1999 return is larger than 10% of mean return Q1-2000.
Table 4 t-test
It is clear that the P-value < alpha (alpha =0.01). Hence the null hypothesis is
significant. Thus it may be summarized that the 1999 return is larger than 10% of mean
return Q1-2000.
Table 5 Confidence interval
Null hypothesis: The mutual fund with higher risk is 50%
Alternative hypothesis: The mutual fund with higher risk is not 50%
The confidence interval is (36.77%, 65.36%). The higher risk of mutual fund lies
within the confidence interval. Hence the null hypothesis is accepted.
Answer to the question 3
Null hypothesis: The 1999 return is not larger than 10% of mean return Q1-2000.
Alternative hypothesis: The 1999 return is larger than 10% of mean return Q1-2000.
Table 4 t-test
It is clear that the P-value < alpha (alpha =0.01). Hence the null hypothesis is
significant. Thus it may be summarized that the 1999 return is larger than 10% of mean
return Q1-2000.

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Answer to the question 4
Table 5 Regression Output
(a) P-value (0.00) < alpha (alpha = 0.05). Hence the model is significant.
(b) All the variables are significant.
(c) 3-yearreturn of funds= 12.69+0.22*return 1999+0.79*return Q1-2000
For return 1999= 102
Return Q1-2000= 9.50
Hence
(d) 3-yearreturn of funds= 12.69+0.22*102+0.79*9.50
= 42.95
Answer to the question 4
Table 5 Regression Output
(a) P-value (0.00) < alpha (alpha = 0.05). Hence the model is significant.
(b) All the variables are significant.
(c) 3-yearreturn of funds= 12.69+0.22*return 1999+0.79*return Q1-2000
For return 1999= 102
Return Q1-2000= 9.50
Hence
(d) 3-yearreturn of funds= 12.69+0.22*102+0.79*9.50
= 42.95
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Bibliography
Amrhein, Valentin, David Trafimow, and Sander Greenland. "Inferential statistics as
descriptive statistics: There is no replication crisis if we don’t expect replication." The
American Statistician 73, no. sup1 (2019): 262-270.
De Winter, Joost CF. "Using the Student's t-test with extremely small sample sizes."
Practical Assessment, Research, and Evaluation 18, no. 1 (2013): 10.
George, Darren, and Paul Mallery. "Descriptive statistics." In IBM SPSS Statistics 23 Step by
Step, pp. 126-134. Routledge, 2016.
Bibliography
Amrhein, Valentin, David Trafimow, and Sander Greenland. "Inferential statistics as
descriptive statistics: There is no replication crisis if we don’t expect replication." The
American Statistician 73, no. sup1 (2019): 262-270.
De Winter, Joost CF. "Using the Student's t-test with extremely small sample sizes."
Practical Assessment, Research, and Evaluation 18, no. 1 (2013): 10.
George, Darren, and Paul Mallery. "Descriptive statistics." In IBM SPSS Statistics 23 Step by
Step, pp. 126-134. Routledge, 2016.
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Keith, Timothy Z. Multiple regression and beyond: An introduction to multiple regression
and structural equation modeling. Routledge, 2014.
McHugh, Mary L. "The chi-square test of independence." Biochemia medica: Biochemia
medica 23, no. 2 (2013): 143-149.
Pandis, Nikolaos. "The chi-square test." American journal of orthodontics and dentofacial
orthopedics 150, no. 5 (2016): 898-899.
Keith, Timothy Z. Multiple regression and beyond: An introduction to multiple regression
and structural equation modeling. Routledge, 2014.
McHugh, Mary L. "The chi-square test of independence." Biochemia medica: Biochemia
medica 23, no. 2 (2013): 143-149.
Pandis, Nikolaos. "The chi-square test." American journal of orthodontics and dentofacial
orthopedics 150, no. 5 (2016): 898-899.
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