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1. Marginal probability of no rain: 0.05+0.1+0.1+0.05=0.32. Marginal probability of heavy rain: 0.1+0.2+0.05+0.01=0.363. Conditional probability that there is Heavy Rain given there is Some Wind (Pr(Rain =Heavy Rain | Wind = Some Wind)) = 0.24. let P(x) be probability of hiring x number of womenthen probability of hiring 3 or fewer women = P(0)+P(1)+P(2)+P(3)now P(0) = (0.6)12 =0.00217P(1) = (0.4)(0.6)11 = 0.00145P(2) = (0.4)2(0.6)10 = 0.00096P(3) = (0.4)3(0.6)9 = 0.00064therefore P(x<=3) = P(0)+P(1)+P(2)+P(3) = 0.005245. The results of a contingency table X2 statistical test performed data: contingency table A B C D1 30 12 33 29 1042 19 18 15 32 843 12 26 8 19 65 61 56 56 80 253expected: contingency table

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