Designing IP Addressing Scheme

Running head: CS 334/CS 534 LAB 6
CS 334/CS 534 Lab 6
Name of the Student
Name of the University
Author’s Note

1
CS 334/CS 534 LAB 6
Part 1: Designing IP Addressing Scheme
a. Five subnets are needed for the topology
b. 3 bits are needed to be borrowed for supporting the number of subnet
c. It can create 8 subnet
d. 30 numbers of usable host IP address is created for each subnet
e. Binary value calculation for the 5 subnets
NET 0 192.168.10. 0 0 0 0 0 0 0 0
NET 1 192.168.10. 0 0 1 0 0 0 0 0
NET 2 192.168.10. 0 1 0 0 0 0 0 0
NET 3 192.168.10. 0 1 1 0 0 0 0 0
NET 4 192.168.10. 1 0 0 0 0 0 0 0
f. The following is the calculation of binary and decimal value of the new subnet mask
a. Binary  11111111.11111111.111111111. 1 1 1 0 0 0 0 0
b. Decimal  255.255.255.224
g. Subnet table
Subnet
Number
Subnet
Address
First Usable
Host Address
Last Usable
Host Address
Broadcast
Address
0 192.168.10.0 192.168.10.1 192.168.10.30 192.168.10.31
1 192.168.10.32 192.168.10.33 192.168.10.62 192.168.10.63
2 192.168.10.64 192.168.10.65 192.168.10.94 192.168.10.95
3 192.168.10.96 192.168.10.97 192.168.10.12
6
192.168.10.127
4 192.168.10.128 192.168.10.129 192.168.10.15
8
192.168.10.159
5 192.168.10.160 192.168.10.161 192.168.10.19
0
192.168.10.191
Assigning IP address to the network device and verification of connectivity
a. 192.168.10.0/27
b. 192.168.10.32/27
c. 192.168.10.64/27
d. 192.168.10.96/27
e. WAN link between R0 and R2: 192.168.10.128/27

2
CS 334/CS 534 LAB 6
Configure IP addressing on R0 and R2 LAN interfaces.