The acupuncture group in population

Running head: STATISTICS
STATISTICS
Name of the Student
Name of the University
Author Note

1.
Given, the sample size of first sample n1 = 8
Sum of square SS1 = 56
Second sample has sample size n2 = 10
Sum of square SS2 = 108
Hence, variance of first sample Var1 = 56/8 = 7
Thus standard deviation first s1 = 2.646
Similarly for second sample Var2 = 108/10 = 10.8
Thus standard deviation of second sample s2 = 3.286
2.
As the control and acupuncture groups are formed from same people hence the people in two
group are related. Also, as the population standard deviation of the groups are unknown and
hence paired t test is applied here.
Null hypothesis(H0): The average difference between control group and acupuncture group
in the population is zero.
Alternative hypothesis (H1): There is significant difference between the control and
acupuncture group in population.
Chosen significance level: 0.05.
From the alternative hypothesis the paired t test is a two tailed t test and the test summary is
given below.
Control Acupu
nture
Diffe
renc

e
23 17 6
20 9 11
24 0 24
17 12 5
30 3 27
18 24 -6
10 14 -4
22 10 12
n 8
df 7
mean 9.375
hypothesize
d mean
0
sd 11.8314
0494
SE 4.18303
3332
t stat 2.24119
6581
p value 0.05997
1921
Decision Not
significa
nt
Hence, from the p value of the t statistics it can be seen that the difference of groups are not
significant at 5% significance level and thus can be concluded that there is not enough
evident to reject the null or the average difference between control group and acupuncture
group in the population is zero.