Null Hypothesis Question Answer 2022

Q U E S T I O N 1
1. Questions 1-3 are for part I of the assignment
You will conduct a one-sample t-test for Writing for the null hypothesis in the
population H
0:
μ = 50, with
α = .05, two tailed. Answer the following questions (report to two
decimal places)
a. Obtain the t-statistic, by hand computation.
b. Obtain the critical value from the t table.
c. Obtain the 95% confidence interval around , by hand
computation.
d. Interpret the confidence interval, according to its definition. (You are not asked to
make a decision on H
0 here yet.) - It can be said with 95% confidence that
the mean writing t score would fall between 51.60 and 53.16.
e. Obtain the p-value from SPSS output.
f. Interpret the p-value, according to its definition. (You are not asked to make a decision
on H
0 here yet.) A small amount of p value provides strong evidence of
null hypothesis rejection.
g. Based on each of the three evidences: t-statistic, CI, and p-value, would you reject H
0?
Why? - Reject null hypothesis, because p value is lower than
significance level.
h. Based on each of the three evidences: t-statistic, CI, and p-value , what can you
conclude about mean Writing scores for the population represented by this
sample? - Mean score falls between the computed confidence interval
and thus, sample is represented by population
4 points
Q U E S T I O N 2
1. Questions 4-13 are for part II of the assignment
Mathew believes that Power Physics will increase the players’ creativity, but doesn’t think
that there is any mechanism by which it could decrease a players creativity. What are the
null and alternative hypothesis for the one-sample z-test in symbols and in words?
6.01
1.964
(51.60, 53.16)
0.00
.

and . The null alternative hypothesis is that the mean posttest score of
Creativity is greater than 7 in the population. The alternative hypothesis is that the
mean posttest score of Creativity is equal to 7 in the population.
and . The null hypothesis is that the mean posttest score of
Creativity is equal to 7 in the population. The alternative hypothesis is that
the mean posttest score of Creativity is greater than 7 in the population.
and . The null alternative hypothesis is that the mean posttest score of
Creativity is greater than 7 in the population. The alternative hypothesis is that the
mean posttest score of Creativity is equal to 7 in the population.
and . The null hypothesis is that the mean posttest score of Creativity
is equal to 7 in the population. The alternative hypothesis is that the mean posttest
score of Creativity is greater than 7 in the population.
0.5 points
Q U E S T I O N 3
1. What is the standard error for the mean posttest creativity score of the pilot sample?
.1
1
.1
7
.5
0
2.
3
0.5 points
Q U E S T I O N 4
1. Suppose the mean of the pilot sample follows a normal distribution with a mean of 7 (from
the null hypothesis). What is the probability of observing a mean posttest score as big or
bigger than the one that Mathew saw in the pilot test (i.e., what is the
p-value)?
.1
0
.1
2
.3
8
.4
0