logo

COA-ITC544 Assignment 1 - Desklib

8 Pages700 Words334 Views
   

Added on  2023-06-12

About This Document

This article provides answers to COA-ITC544 Assignment 1 questions on conversions, representation of values, Boolean algebra identities, and more. The subject code is ITC544, and the course is Computer Architecture and Organization. The article is relevant to students studying in CSU-Melbourne.

COA-ITC544 Assignment 1 - Desklib

   Added on 2023-06-12

ShareRelated Documents
COA-ITC544 Assignment 1
Computer Architecture and Organization
Student name:Wasif Numan
Student ID Number:11640426
Subject Code: ITC544
CSU-Melbourne
COA-ITC544 Assignment 1 - Desklib_1
COA-ITC544-Assignment 1
Table of Contents
Answer to Question 1:.................................................................................................................2
A.) Value of base x if (152)x = (6A) 16......................................................................................2
b) Conversions.............................................................................................................................2
c) Representation of value..........................................................................................................4
Question 2:.......................................................................................................................................5
a) Prove........................................................................................................................................5
b)Using basic Boolean algebra identities for Boolean variables x, y, and z, for prove...............6
c) Prove:......................................................................................................................................7
1
COA-ITC544 Assignment 1 - Desklib_2
COA-ITC544-Assignment 1
Answer to Question 1:
A.) Value of base x if (152)x = (6A) 16
The value of base is considered as X
Provided:
(152) x = (6A) 16
Or, X^2 + 5X + 2*X = 6*16 + A
Or, X^2 + 5X + 2*X = 6*16 + 10
X^2 + 5X + 2 = 106
X^2 + 5X- 104 = 0
X^2 + 13X- 8X – 104 = 0
X (X + 13) – 8(X + 13) = 0
(X - 8) (X + 13) = 0
X = 8 and X = -13
Therefore the value of X is 8.
b) Conversions
i) BED16 converting to base-3
= B * 16*16 + E * 16 + D
= 2816 + 224 + 13
= (3053)10
2
COA-ITC544 Assignment 1 - Desklib_3

End of preview

Want to access all the pages? Upload your documents or become a member.

Related Documents
Computer Architecture and Organization - Study Material and Solved Assignments
|8
|721
|92

Computer Architecture and Organization - Study Material and Solved Assignments
|9
|829
|127

Computer Architecture and Organization
|9
|841
|314

Computer Architecture and Organization - Study Material and Solved Assignments
|9
|831
|251

Computer Architecture and Organization: Advance Computer Architecture
|9
|846
|432

Data Representation and Digital Logic Assignment
|9
|817
|492