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Computer Architecture and Organization - Study Material and Solved Assignments

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Added on  2023-06-12

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This study material covers topics such as conversions, representation of values, Boolean algebra identities and more related to Computer Architecture and Organization. It also includes solved assignments and proofs. The course code is ITC544.

Computer Architecture and Organization - Study Material and Solved Assignments

   Added on 2023-06-12

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Running head: COMPUTER ARCHITECHTURE AND ORGANIZATION
Computer Architecture and Organization
Full name:
Student ID:
Subject Code: ITC544
Author’s Note
Computer Architecture and Organization - Study Material and Solved Assignments_1
1
COMPUTER ARCHITECHTURE AND ORGANIZATION
Table of Contents
Question 1:.......................................................................................................................................2
a.) Determining the value of base x if (152) x = (6A) 16............................................................2
b) Conversions.............................................................................................................................2
c) Representation of value..........................................................................................................5
Question 2:.......................................................................................................................................5
a) Prove........................................................................................................................................5
b) Using basic Boolean algebra identities for Boolean variables x, y, and z, for prove..............7
c) Prove:......................................................................................................................................7
Computer Architecture and Organization - Study Material and Solved Assignments_2
2
COMPUTER ARCHITECHTURE AND ORGANIZATION
Answer to Question 1:
A.) Value of base x if (152) x = (6A) 16
The value of base is considered as X
Provided:
(152) x = (6A) 16
Or, X^2 + 5X + 2*X = 6*16 + A
Or, X^2 + 5X + 2*X = 6*16 + 10
X^2 + 5X + 2 = 106
X^2 + 5X- 104 = 0
X^2 + 13X- 8X – 104 = 0
X (X + 13) – 8(X + 13) = 0
(X - 8) (X + 13) = 0
X = 8 and X = -13
Therefore the value of X is 8.
b) Conversions
i) BED16 converting to base-3
= B * 16*16 + E * 16 + D
= 2816 + 224 + 13
= (3053)10
Computer Architecture and Organization - Study Material and Solved Assignments_3

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