Data and IT Assignment
Added on 2022-12-08
29 Pages3586 Words456 Views
Running head: DATA AND IT ASSIGNMENT
Data and IT Assignment
Name of the Student:
Name of the University:
Author Note:
Data and IT Assignment
Name of the Student:
Name of the University:
Author Note:
DATA AND IT ASSIGNEMENT
1
Table of Contents
Assessment Part 1......................................................................................................................3
Section 1.................................................................................................................................3
Solution 1...........................................................................................................................3
Solution 2...........................................................................................................................3
Solution 3...........................................................................................................................3
Solution 4...........................................................................................................................4
Solution 5...........................................................................................................................4
Solution 6...........................................................................................................................5
Solution 7...........................................................................................................................5
Solution 8...........................................................................................................................6
Solution 9...........................................................................................................................6
Solution 10.........................................................................................................................7
Section 2.................................................................................................................................7
Solution 11.........................................................................................................................7
Solution 12.........................................................................................................................9
Assignment Part 2....................................................................................................................10
Introduction..........................................................................................................................12
Descriptive Statistics............................................................................................................12
Graphical Presentation.........................................................................................................16
Scatter Diagram to Explore Relationship.............................................................................21
Probability of married people with more than £500 spending.............................................24
1
Table of Contents
Assessment Part 1......................................................................................................................3
Section 1.................................................................................................................................3
Solution 1...........................................................................................................................3
Solution 2...........................................................................................................................3
Solution 3...........................................................................................................................3
Solution 4...........................................................................................................................4
Solution 5...........................................................................................................................4
Solution 6...........................................................................................................................5
Solution 7...........................................................................................................................5
Solution 8...........................................................................................................................6
Solution 9...........................................................................................................................6
Solution 10.........................................................................................................................7
Section 2.................................................................................................................................7
Solution 11.........................................................................................................................7
Solution 12.........................................................................................................................9
Assignment Part 2....................................................................................................................10
Introduction..........................................................................................................................12
Descriptive Statistics............................................................................................................12
Graphical Presentation.........................................................................................................16
Scatter Diagram to Explore Relationship.............................................................................21
Probability of married people with more than £500 spending.............................................24
DATA AND IT ASSIGNEMENT
3
Assessment Part 1
Section 1
Solution 1
8-4
4
Solution 2
Let, 49 equates to the x% of 70.
Therefore, 70∗x %=49
70∗x
100 =49
x= 49∗100
70
x=7∗10=70
Hence, 49 is 70% of the 70.
Solution 3
Solution 3.A
Fraction Percentage
45
100 = 9
20 45%
2
3
2
3∗100= 200
3 %=66.67 %
22.5
100 = 9
40 22.5%
3
Assessment Part 1
Section 1
Solution 1
8-4
4
Solution 2
Let, 49 equates to the x% of 70.
Therefore, 70∗x %=49
70∗x
100 =49
x= 49∗100
70
x=7∗10=70
Hence, 49 is 70% of the 70.
Solution 3
Solution 3.A
Fraction Percentage
45
100 = 9
20 45%
2
3
2
3∗100= 200
3 %=66.67 %
22.5
100 = 9
40 22.5%
DATA AND IT ASSIGNEMENT
4
7
5
7
5∗100=140 %
Solution 3.B
Total number of cereal bars in a carton is 150.
Number of students in the class is 20.
The number of cereal bars for each student is
total number of cereal bars
number of students = 150
20
Hence, when 150 cereal bars are distributed to the whole class then each student will get 1
20
of 150 cereal bars. Thus, the average cereal bars for each student is 15
2 .
Solution 4
Samuel gave three £50 notes for the tickets that means he paid (3*£50) = £150 for the tickets.
He received £4.20 change after paying £150.
So, the net spending on tickets is £ (150-4.20) = £145.80.
Hence, the price for each ticket is £ 145.80
3 =£ 48.60.
Solution 5
Solution 5.A
Binary addition,
10011+10101=101000
4
7
5
7
5∗100=140 %
Solution 3.B
Total number of cereal bars in a carton is 150.
Number of students in the class is 20.
The number of cereal bars for each student is
total number of cereal bars
number of students = 150
20
Hence, when 150 cereal bars are distributed to the whole class then each student will get 1
20
of 150 cereal bars. Thus, the average cereal bars for each student is 15
2 .
Solution 4
Samuel gave three £50 notes for the tickets that means he paid (3*£50) = £150 for the tickets.
He received £4.20 change after paying £150.
So, the net spending on tickets is £ (150-4.20) = £145.80.
Hence, the price for each ticket is £ 145.80
3 =£ 48.60.
Solution 5
Solution 5.A
Binary addition,
10011+10101=101000
DATA AND IT ASSIGNEMENT
5
Solution 5.B
0.0101=10−1.9957
Solution 6
Solution 6.A
The amount of spending with discount is £100.
The amount of discount is 20%.
Hence, the total price without discount is
£ 100
(1− 20
100 )
= £ 100
4
5
= £ 100∗5
4 =£ 125.
Now, the total savings is £ (125-100) = £25.
Solution 6.B
The average savings amount for 4 hairdos is £ 25
4 =£ 6.25.
Solution 7
Solution 7.A
The average of the seven numbers
Average= Summation of the givennumbers
Total numbers that are given
Average=5+ 12+12+ 8+4 +10+5
7
Average=56
7
Average=8
Solution 7.B
The mode is that value which occurs most often in a series.
5
Solution 5.B
0.0101=10−1.9957
Solution 6
Solution 6.A
The amount of spending with discount is £100.
The amount of discount is 20%.
Hence, the total price without discount is
£ 100
(1− 20
100 )
= £ 100
4
5
= £ 100∗5
4 =£ 125.
Now, the total savings is £ (125-100) = £25.
Solution 6.B
The average savings amount for 4 hairdos is £ 25
4 =£ 6.25.
Solution 7
Solution 7.A
The average of the seven numbers
Average= Summation of the givennumbers
Total numbers that are given
Average=5+ 12+12+ 8+4 +10+5
7
Average=56
7
Average=8
Solution 7.B
The mode is that value which occurs most often in a series.
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