Numeracy Data and IT

Using numeracy data and IT

TABLE OF CONTENTS
ASSESSMENT PART 1..................................................................................................................1
SECTION 1..................................................................................................................................1
SECTION 2..................................................................................................................................5
ASSESSMENT PART 2 ...............................................................................................................11
REFERENCES .............................................................................................................................20

ASSESSMENT PART 1
SECTION 1
Question 1
Result of the calculation
Solution: ||||
Question 2
__ % of 70 = 49
Solution
(49/70)/100 = 70
So 49 equate to 70% of 70.
Check:
(70*70)/100 = 49
Question 3
a.)
Equivalent fractions and percentages:
For converting any fraction into percentage at first division is used so that fraction can be
changed into decimal. The obtained decimal number is multiplied by 100 to get the equivalent
percentage value of the fraction (Botchkarev, 2015). Similarly, to convert a percentage into
fraction percent is written in numerator and in denominator 100 is written. The ratio is then
simplified to obtain the fractional value.
Fraction Percentage
(9/20) 45.00%
(2/3) 66.66%
(9/40) 22.50%
(7/5) 140.00%
1

1.)
A carton contains 150 cereal bars.
What fraction of this number will each person get when distributed to a class of 20
students?
Solution
Total number of students = 20
Total number of bars = 150
Fraction distributed to each person = 150/20 = 15/2
Question 4
Samuel paid cash for 3 discount-priced football tickets. He was given £4.20 change from
the three £50 notes he tendered. What was the price of each ticket? Show your working.
Solution
Amount paid by Samuel = 3 notes of £50 = £3*50
The change received for 3 tickets = £4.20
Change received for 1 ticket = £4.20 /3 = £1.4
Price of one ticket = £50 - £1.4 = £48.6
Question 5
a.) Solve this binary arithmetic: 10011 +10101
Solution
For performing two bit binary addition following truth table is used in which A and B are
inputs, S is sum and C is the carry (Bennett and et.al., 2016).
A B S C
0 0 0 0
0 1 1 0
1 0 1 0
1 1 0 1
Binary arithmetic: 10011 + 10101
2

10011 + 10101 = 101000
Check
(10011)₂ = 19
(10101)₂ = 21
19 +21 = 40 = 101000
b.) Write the number 0.0101 as a power of 10.
Solution
0.0101 = 1.01*10ˉ
Question 6
As a promotional offer, a new hair salon offered its services at 20% discount for the first 2
weeks. Janice and her friends took advantage of the bargain and had their hair done for a
total amount of £100. Show your working.
Solution
a.) What were the total savings made?
Solution
Total amount paid by Jancie and her friends = £100
The discount offered by salon = 20%
Actual amount liable to pay prior to discount = 120% of £100
= (120/100)*100 = £120
The total savings made = £120 - £100 = £20
b.) Work out the average savings amount if 4 hairdos were done?
Solution
Number of hair done = 4
The total amount saved for 4 hair dons = £120 - £100 = £20
Average amount saved= £20 /4 = £5
3

Question 7
Here are seven numbers.
Numbers: 5 12 12 8 4 10 5
Solution
a.) Mean of the seven numbers.
The mean is defined as the arithmetic average of the given numbers and is the central
value. It can be obtained by dividing the sum of data set values to the total number of values in
the sequence (George and Mallery, 2016).
Mean = (Sum of values / Total number of values )
Mean = (5 +12+12+8+4+10+5) / 7
Mean = 8
b.) Mode of the seven numbers
Mode is defined as the number which occurs most frequently in the series (Park, 2015). Thus, the
number which has maximum frequency in the series is called mode. In the given series of
numbered 12 occurs maximum times (frequency =2) thus it is defined as mode.
Mode = 12
Question 8
80 men and 120 women were asked if they enjoyed watching football.
Altogether 3 / 5 of the people said yes.
9 / 10 of the men said yes.
What fraction of the women said yes?
Solution
Total number of men = 80
Total number of women = 120
Total participants = 200
Participants who said yes = (3/5) of total = (3/5)*200 = 120
Men who said yes = (9/10)*80 = 72
Women who said yes = 120-72 = 48
Women who enjoyed match = 48
4