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CVEN9625 Fundamentals of Water Engineering

   

Added on  2020-02-18

5 Pages864 Words325 Views
RUNNING HEAD: FUNDAMENTALS OF WATER ENGINEERINGNAMEUNITASSIGNMENTASSESSMENT NUMBER

RUNNING HEAD: FUNDAMENTALS OF WATER ENGINEERINGQn. 1:a)Friction on hydraulic hoist:Ram Diameter = 32cm,Outer Diameter = 32.02cmViscosity = 0.14Pa.sDensity = 820Kg/m3. Speed = 0.20m/sLength = 4mRam x-sec = 0.162 * 3.142 = 0.08m2.Volume = 0.08m2 * 4 = 0.322m3.Mass = 0.322 * 820= 263.79Kg.Friction force = 263.73 * 9.81 * 0.14= 326.29NQn. 3a)Buoyancy force arises when an object is submerged into a fluid with a heavier density. The fluid with a heavier density will push up the object due to action of gravity which has a stronger effect on objects or fluids with relatively more weight.b)Resultant force on plug only due to water:Radius of plug = 0.28mDepth at the top = 0.35mDepth at bottom = 0.50mDensity = 1000kg/m3Pressure at the top of cone: ρgh1A1=1000 * 9.81 * 3.142 * 0.282 * 0.35=895.67NPressure at the bottom of cone: ρgh2A2=1000 * 9.81 * (total surface area of plug-surfacearea of plugged part) * sin θ=246.43NTotal force exerted by the water =895.67 – 246.43 = 649.2Nc)Depth of water that will result in no resultant force:In this case, pressure at top = pressure at bottom.Pressure at bottom=246.43246.43N =ρghA1 = 1000 * 9.81 * hh= 246.43 / (1000 * 9.81 * 0.246)=10.21cm1

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